Since the two vertices are touching the circle, all angles have to be 60o
And the height of the half triangle using pythogoras theorem will be=1/2
and similarly, the base-rt3/2
hence, the total area of the triangle will be rt3/4
Hence, A
The alphabets are basically used to represent the advisors. The common advisors in three groups are represented in RED whereas the ones common in two groups are marked with the same color.
Can you please explain the 9th class probability?
Which is the initial velocity in this case-is it the one during the 2nd second? Is it 2 miles/1 sec (2nd sec)
And then the acceleration would be- 6=2+1/2at^2
t is 4 sec
6=2+8a
a=0.5
distance travelled in 7 secs from 2nd second
2+1/2 X0.5X 49=14.25
distance travelled in 6 secs after 2nd sec
2+1/2X 0.5X36=11
Is it 14.25-11=3.25?
The exact equation for speed (miles/hr)should be:
Let distance be x
x/ y+1/4.....1
x/ y-1/12.....2 (y hrs and 5 mins less)
Now, the puzzle for me is average speed for the second day and not for both days. Average speed for 16th May should be the speed as mentioned in 2 but if it is the average speed for both days then
total distance/ total time
2x/ 2y+1/6 or 12x/ 12y+1
Please let me know if I am wrong!