For the second problem,
x = 50y + 69. y must be even. If it were odd, then x would be even.
Type: Posts; User: Jesus Christ; Keyword(s):
For the second problem,
x = 50y + 69. y must be even. If it were odd, then x would be even.
The way I see it, the only possible answers are 13 and 5, neither of which options. Are you sure it is not between W and Z? It would make more sense.
(I) Counter example. If the units digit of a is 5 and the units digit of b is 5 then the units digit of a + b will be 0. So (I) is false.
(II) Since the tens digit of a is 8, this will be true. ...
The trick here is basically to identify that 2/2^m = 1/2^(m-1). If you know that you are golden.
This is a tricky questions because it deals with time series data. For 1992 there are 6 data points which means to get the meadian we should look at the 3rd and 4th highest values, not the 3rd and...
This looks a little suspect. They first leave the radical out and then in the second line they put it back in, but they have a 2 under the radical. I'd say it is an error.
Interesting.
The prime factorization of 30 is 2*3*5. To be divisible by 12 we need another 2* in the front of this thing, which will only happen with the even multiples. Since there are 12 total...
7x + 3y = 12
3x + 7y = 6
Subtract the second from the first...
(7x + 3y) - (3x + 7y) = 12 - 6
Notice since 3x + 7y = 6, we subtracted the same number from each side so the equality still holds....
Just use an example.
Let c = 12 and d = 18. Then m = 6.
gcf of c + d = 30 and 12 is 6.
gcf of 2 + d = 20 and 12 is 4.
gcf of cd = 216 and 12 is 12.
gcf of 2d = 36 and 12 is 12.
gcf of ...
You need the prime factorization of each.
1000 = 2*2*2*5*5*5
68 = 2*2*17
So the greatest prime factor of 1000 is 5 and the greastes prime factor of 68 is 17.
If BC went through the center of the circle then x would = 90. It specifically says that it's not the diameter, so we know x <> 90. We do not know the position of BC. if the center of the circle...
Good catch! They fooled me.
43/60 is correct. In my formula, just switch the (2/3) and the (1/3).
(2/3)*(75/100)+(1/3)*(70/100) = 220/300 = 11/15
Adding to the second part of my reply, the question is probably not best looked at as a combination question, but you COULD do the following if you really wanted to:
Total combinations of 2...
((1/10)+1/(1/10))(1/(1/10))= 10.1 * 10 = 101
34/100 * 33/99 = 1122/9900 = 17/150
34/100 is the probablilty that the first selected student came from a 2-year community college. Now that one...