The practice paper based test on the ets website

[leckie504]

Hello I am taking the Gre on July 22 and I wanted to know if there is anyone who has the explanations to the practice paper based test on the ets website. And I would also like the explanations for the practice problems on the Preparing for the Verbal and Quantitative Sections of the Gre General Test. I am having a hard time trying to figure some of the questions out. Also if I just study the test prep on the ets website how well will I do I am not very good at math. Thanks for your time.

[NDure]

Hi I only have a website for the New GRE, not the current one. But how about you post the questions here and we can help you out with them

[leckie504]

If 3 times Jane’s age, in years, is equal to 8 times Beth’s age, in years, and

the difference between their ages is 15 years, how old are Jane and Beth?

[twohundredping]

Let J represent Jane and B represent Beth.

 

3 * J = 8 * B

 

Now for the second equation we need to know who the older person is. We can use the first equation to tell us who is older. Either do:

J = 8/3 * B (this tells us that J is almost 3 times the age of B)

 

OR

 

B = 3/8 * J (this tells us that B is less than 1/2 the age of J)

 

So now we know J is older than B. The second equation will be J - B = 15.

Now we need to solve the system of equations

3*J = 8*B

J - B = 15

 

I will solve the second equation for J and plug it into the first equation

J = 15 + B

3 * (15 + B) = 8 * B

45 + 3*B = 8*B

45 = 5*B

B = 9

 

Now we can plug B back into any equation. I will choose the equation J - B = 15

J - 9 = 15

J = 24

 

Therefore, Jane is 24 and Beth is 9. You can plug the values back in to the original two equations to check your work.

[NDure]

if 3 times jane’s age, in years, is equal to 8 times beth’s age, in years, and

the difference between their ages is 15 years, how old are jane and beth?

 

3j = 8b

 

j-b = 15, j = b +15

 

3(b+15)=8b

3b+45 = 8b

b= 45/5 = 9

 

j = 9+ 15 = 24

[leckie504]

In the coordinate system below, find the

(a) coordinates of point Q

(b) perimeter of PQR

© area of PQR

(d) slope, y-intercept, and equation of the line passing through

points P and R

 

19. In the xy-plane, find the

(a) slope and y-intercept of a graph with equation 2y x 6

(b) equation of the straight line passing through the point (3, 2) with

y-intercept 1

© y-intercept of a straight line with slope 3 that passes through the

point (2, 1)

(d) x-intercepts of the graphs in (a), (b), and ©

33

[leckie504]

I cant figure out how to paste the angle but I uploaded it as an a attachment.

[leckie504]

17. If 3 times Jane’s age, in years, is equal to 8 times Beth’s age, in years, and

the difference between their ages is 15 years, how old are Jane and Beth?

18. In the coordinate system below, find the

(a) coordinates of point Q

(b) perimeter of PQR

© area of PQR

(d) slope, y-intercept, and equation of the line passing through

points P and R

19. In the xy-plane, find the

(a) slope and y-intercept of a graph with equation 2y + x = 6

(b) equation of the straight line passing through the point (3, 2) with

y-intercept 1

© y-intercept of a straight line with slope 3 that passes through the

point (2, 1)

(d) x-intercepts of the graphs in (a), (b), and ©

33

[twohundredping]

18. Answered in your other thread

19.

(a) We can put the equation in slope intercept form where it is easy to see the slope and y-intercept.

Slope intercept form: y = m*x + b, where m is the slope and b is the y-intercept

2y + x = 6

2y = 6 - x

y = 3 - x/2 = -x/2 + 3 = -1/2 * x + 3

 

Therefore, the slope is -1/2 and the y-intercept is 3.

 

(b) Here they gave us one point (3, 2) and told us the y-intercept is 1. There are two approaches we can use to solve the problem from here.

 

Approach 1:

y = m*x + b

Since the y-intercept is 1, b = 1

y = m*x + 1

Now we can plug in the point (3,2) for x and y.

2 = m * 3 + 1

1 = 3m

m = 1/3

So the equation of the line is:

y = 1/3 * x + 1

 

We can plug in the point (3,2) to verify that we did everything correctly

 

Approach 2:

Since the y-intercept is 1, we know that b = 1 and that the point (0, 1) is on the line.

Now we can find the slope between (3,2) and (0,1) as:

(2 - 1) / (3 - 0) = 1/3

Now we can give the equation of the line as:

y = 1/3 * x + 1

 

We can plug in the point (3,2) to verify that we did everything correctly

 

© y = 3 * x + b

Now plug in the point they give you.

1 = 3 * 2 + b

-5 = b

So y = 3 * x - 5 is the equation of the line.

 

(d) The x-intercept is the point where y = 0.

x-intercept of (a): 2x + 0 = 6

x = 3 is the x-intercept

 

x-intercept of (b): 0 = 1/3 * x + 1

-1 = 1/3 * x

x = -3 is the x-intercept

 

x-intercept of (x): 0 = 3 * x - 5

5 = 3 * x

x = 5/3 is the x-intercept

[leckie504]

18. Answered in your other thread

19.

(a) We can put the equation in slope intercept form where it is easy to see the slope and y-intercept.

Slope intercept form: y = m*x + b, where m is the slope and b is the y-intercept

2y + x = 6

2y = 6 - x

y = 3 - x/2 = -x/2 + 3 = -1/2 * x + 3

 

Therefore, the slope is -1/2 and the y-intercept is 3.

 

(b) Here they gave us one point (3, 2) and told us the y-intercept is 1. There are two approaches we can use to solve the problem from here.

 

Approach 1:

y = m*x + b

Since the y-intercept is 1, b = 1

y = m*x + 1

Now we can plug in the point (3,2) for x and y.

2 = m * 3 + 1

1 = 3m

m = 1/3

So the equation of the line is:

y = 1/3 * x + 1

 

We can plug in the point (3,2) to verify that we did everything correctly

 

Approach 2:

Since the y-intercept is 1, we know that b = 1 and that the point (0, 1) is on the line.

Now we can find the slope between (3,2) and (0,1) as:

(2 - 1) / (3 - 0) = 1/3

Now we can give the equation of the line as:

y = 1/3 * x + 1

 

We can plug in the point (3,2) to verify that we did everything correctly

 

© y = 3 * x + b

Now plug in the point they give you.

1 = 3 * 2 + b

-5 = b

So y = 3 * x - 5 is the equation of the line.

 

(d) The x-intercept is the point where y = 0.

x-intercept of (a): 2x + 0 = 6

x = 3 is the x-intercept

 

x-intercept of (b): 0 = 1/3 * x + 1

-1 = 1/3 * x

x = -3 is the x-intercept

 

x-intercept of (x): 0 = 3 * x - 5

5 = 3 * x

x = 5/3 is the x-intercept

 

 

 

 

 

 

OMG! Thank u so much!

[Anu]

For the question , In the XY plane, find the following,

© The Y intercept of a line with slope 3 that passes through the point (-2,1)

From the Ques, we can say Y= 3x+b Now plug in the value (-2,1) ,

1= 3( -2) + b

1+6 = b

7= b ( Thats the answer for the C )

So, y = 3x -7 is the equation

Now coming to the (d) The x- intercept of the graphs in (a),(b),©

X- intercept means y=0

(a) 2y+x= 6

Since Y= 0, x= 6(thats the answer)

(B) Y=X/3 +1

Since Y=0, X= -3(thats also the answer)

© Y= 3x-7

Since Y= 0, x= -7/3 (also te answer)

[dominiquej]

I have a quick question about D.

 

 

18. Answered in your other thread

19.

(a) We can put the equation in slope intercept form where it is easy to see the slope and y-intercept.

Slope intercept form: y = m*x + b, where m is the slope and b is the y-intercept

2y + x = 6

2y = 6 - x

y = 3 - x/2 = -x/2 + 3 = -1/2 * x + 3

 

Therefore, the slope is -1/2 and the y-intercept is 3.

 

(b) Here they gave us one point (3, 2) and told us the y-intercept is 1. There are two approaches we can use to solve the problem from here.

 

Approach 1:

y = m*x + b

Since the y-intercept is 1, b = 1

y = m*x + 1

Now we can plug in the point (3,2) for x and y.

2 = m * 3 + 1

1 = 3m

m = 1/3

So the equation of the line is:

y = 1/3 * x + 1

 

We can plug in the point (3,2) to verify that we did everything correctly

 

Approach 2:

Since the y-intercept is 1, we know that b = 1 and that the point (0, 1) is on the line.

Now we can find the slope between (3,2) and (0,1) as:

(2 - 1) / (3 - 0) = 1/3

Now we can give the equation of the line as:

y = 1/3 * x + 1

 

We can plug in the point (3,2) to verify that we did everything correctly

 

© y = 3 * x + b

Now plug in the point they give you.

1 = 3 * 2 + b

-5 = b

So y = 3 * x - 5 is the equation of the line.

 

(d) The x-intercept is the point where y = 0.

x-intercept of (a): 2x + 0 = 6

x = 3 is the x-intercept

 

x-intercept of (b): 0 = 1/3 * x + 1

-1 = 1/3 * X WHat did you do here to get -3?

x = -3 is the x-intercept Can you help me understand how you got this -3?

 

x-intercept of (x): 0 = 3 * x - 5

5 = 3 * x

x = 5/3 is the x-intercept

[dominiquej]

on D, part B....how did you get -3? I cant figure it out