roch Posted July 16, 2011 Share Posted July 16, 2011 (edited) 1) In rectangle ABCD, sides AD and BC have been divided in to segments of equal length as shown. Col A Col B The length of EF The length of EF Answer is B 2) Among the 900 spectators at a football game , there was a total of x students from college C and a total of y students who were not from college C col A : the number of spectators at the game who were not students col B : 900-x-y Edited July 16, 2011 by roch Quote Link to comment Share on other sites More sharing options...
Megamind Posted July 16, 2011 Share Posted July 16, 2011 1) In rectangle ABCD, sides AD and BC have been divided in to segments of equal length as shown. Col A Col B The length of EF The length of GC here the bases has been divided into equal lengths GC = √GD^2+ CD^2 EF = √FX^2 + XE^2 since GD (4 segments) is > FX (3 segments), and CD = XE, then GC must be bigger than EF 2) Among the 900 spectators at a football game , there was a total of x students from college C and a total of y students who were not from college C col A : the number of spectators at the game who were not students col B : 900-x-y since the total is 900 and all students there = x+y, then the (not students) attending = 900 - x -y, so C Quote Link to comment Share on other sites More sharing options...
roch Posted July 16, 2011 Author Share Posted July 16, 2011 Thank you Megamind... Quote Link to comment Share on other sites More sharing options...
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