choked Posted May 10, 2012 Share Posted May 10, 2012 I'm having a lot of trouble making my answer look like the OA. Can someone help? Here's the problem: In how many different ways can 12 people be seated at two tables with one seating 7 and the other seating 5? OA is 13,685,760, which, I think, comes from 12P5*4!*3!. Prime factorization of the OA yields 2^10*3^5*5*11, which I figured must look something like (12*11*10*9*8*4*4*3*3). Anybody want to help me out with this problem? Quote Link to comment Share on other sites More sharing options...
choked Posted May 11, 2012 Author Share Posted May 11, 2012 Nevermind. I figured it out, no thanks to any of you. 12C5*6!*4! thanks for nothing. Quote Link to comment Share on other sites More sharing options...
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