Tanzid Ahmed Posted June 17, 2014 Share Posted June 17, 2014 There was a leakage in the container of the refined oil. If 11 kg oil is leaked out per day then it would have lasted for 50 days, If the leakage was 15 kg per day, then it would have lasted for only 45 days. For how many days would the oil have lasted if there was no leakage and it was completely used for eating purpose 1) 72 2) 84 3)105 4)64 Quote Link to comment Share on other sites More sharing options...
rajechP Posted June 24, 2014 Share Posted June 24, 2014 Say the consumption per day for eating = x kg./day, so for the first case, Total oil= 50*(11+x) kg.; and for the second case, Total oil= 45*(15+x) kg.. Since 50*(11+x) = 45*(15+x) => x = 25 kg/day; So, the oil will past for 50*[(11+25)/25] = 50*(36/25)=72 days. Option A. Quote Link to comment Share on other sites More sharing options...
BGPC Eliza Posted November 14, 2014 Share Posted November 14, 2014 I think that is a great idea to start by giving the consumption per day a variable, like x then you have 50 days*(11+xkg/day)=0 45 days*(15+x kg/day) =0 And then yes, you can set them equal to each other to get 50 days*(11+xkg/day)=45 days*(15+x kg/day) to break it down a bit more, you can divide both sides by 5 to get 10(11+x)=9(15+x) then you multiply everything out 110+10x=135+9x isolate the x x=25 so now you know the rate is 25kg/day you can use that to figure out how much oil is in the barrel to begin with 50 days (36 kg/day)= 1800kg (25kg/day)x days=1800 1800/25=72 The answer is 72 days Quote Link to comment Share on other sites More sharing options...
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