2007 September 9th, 07:33 AM
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#2 (permalink) |
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Within my grasp!
 Join Date: Jul 2007
Posts: 261
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is m+z positive?
(1) m>3z m=1, z=-2, => 1-2=neg m=2 z=.5 => 2-.5=pos insufficient. (2) 4z>m z=-1 m=-5 -5+-1=neg z=1, m=.5 .5+1=pos insufficient 1 and 2 combined, you get following inequality. 3z<m<4z. in order to satisfy this condition, z must be positive which in then makes m positive so m+z will be positive. C |
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2007 September 13th, 07:27 AM
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#4 (permalink) |
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TestMagic Guru-in-Training
Join Date: Jun 2007
Location: Gurgaon, India
Posts: 740
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Another vote for C.
for m+z>0, both must be +ve or lml > lzl and m must be +ve. From stmnt 1 we get to know that m is +ve. stmnt II states z is +ve. So, C!
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