Let the three charities be X, Y, Z. We are told that 8 people are in each charity board. So, let's identify the board positions as
X1, X2, X3, X4, X5, X6, X7, X8
Y1, Y2, Y3, Y4, Y5, Y6, Y7, Y8
Z1, Z2, Z3, Z4, Z5, Z6, Z7, Z8
Exactly 4 people serve on charity X, Y and Z.
So, X1, X2, X3, X4 = Y1, Y2, Y3, Y4, = Z1, Z2, Z3, Z4.
Each pair of charities has 5 persons in common.
Since each pair of charities already has 4 people in common, we need to add the fifth. i.e, one more person in common between two charities.
X5 = Y5, Y6 = Z5, X6 = Z6.
So, the total number of board members at this point is 7 occupying 6 seats in each board.
There are still 2 board positions remaining for each charity and each board position is occupied by a unique person. So, that makes a total of 6 people occupying the remaining 6 board positions (2 for X, 2 for Y and 2 for Z)
So, the total number is 7+6 = 13. Option B.



LinkBack URL
About LinkBacks







Reply With Quote


Bookmarks