weirdo Posted September 12, 2006 Share Posted September 12, 2006 If the length and width of a rectangular diagram 12 inches by 8 inches are to be reduced by the same percent so that the diagram will exactly fit into a rectangular space 4.5 inches by 3 inches, by what percent should the dimensions be reduced? (A) 25% (B) 37.5% © 62.5% (D) 75% (E) 87.5% In a certain community, 39,285 more apartments were converted to condominiums and sold in 1981 than in 1980. If this was a 30 percent increase, how many apartments were converted and sold in 1981? (A) 11,786 (B) 51,070 © 91,665 (D) 130,950 (E) 170,235 i got these from korean pdf..the second one says asnwer is e, but i got D..and i am not been able to solve first one quickly, answer is c for first thanks Quote Link to comment Share on other sites More sharing options...
Annie9 Posted September 12, 2006 Share Posted September 12, 2006 for the the first Q I used POE; since the lenght is reduced from 12 to 4.5 and breadth from 8 to 3 inches; then its been reduced a little more than 50% but i would like to know how to solve it mathematically! for the second one x * 30% = 39,285 soving for x you get 130,950 Quote Link to comment Share on other sites More sharing options...
bscout Posted September 12, 2006 Share Posted September 12, 2006 [1] x/39,285 = 100/30 ==> x = 130,950. Answer D. OA is wrong. Quote Link to comment Share on other sites More sharing options...
Zephyr Posted September 12, 2006 Share Posted September 12, 2006 The answers for both questions are correct. If the length and width of a rectangular diagram 12 inches by 8 inches are to be reduced by the same percent so that the diagram will exactly fit into a rectangular space 4.5 inches by 3 inches, by what percent should the dimensions be reduced? (A) 25% (B) 37.5% © 62.5% (D) 75% (E) 87.5%We have increase in length=12-4.5 = 7.5 % increased in length=(7.5 / 12) X 100 % =62.5 % Increase in breadth= 8 – 3 =5 % increased in breadth = (5/8) X 100% =62.5 % 2 )In a certain community, 39,285 more apartments were converted to condominiums and sold in 1981 than in 1980. If this was a 30 percent increase, how many apartments were converted and sold in 1981? (A) 11,786 (B) 51,070 © 91,665 (D) 130,950 (E) 170,235 say in 1980 “x” apartments were sold. We have Increase in 1981 = 39285 (30/100) x = 39285 =>x=130950 so in 1981 no. of apartments sold= no. sold in 1980 + increase in 1981 = x + 39285 =170235 I hope the solution is clear… Quote Link to comment Share on other sites More sharing options...
Annie9 Posted September 12, 2006 Share Posted September 12, 2006 I read the Q wrong! I agree with Zephyr for 2nd one; its indeed D, not C Quote Link to comment Share on other sites More sharing options...
weirdo Posted September 13, 2006 Author Share Posted September 13, 2006 thanks a lot folks Quote Link to comment Share on other sites More sharing options...
bscout Posted September 13, 2006 Share Posted September 13, 2006 The answers for both questions are correct. say in 1980 “x” apartments were sold. We have Increase in 1981 = 39285 (30/100) x = 39285 =>x=130950 so in 1981 no. of apartments sold= no. sold in 1980 + increase in 1981 = x + 39285 =170235 I hope the solution is clear… Dammit! :doh: Thanks Zephyr. Quote Link to comment Share on other sites More sharing options...
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