Number has to be of the form:
52x + 33 & 117y + 98
or
78x+59 & 117y + 98
Following any of the two conditions, a number which satisfies both condition can be found. All we need to do then is to check whether it satisfies the third condition too.
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What is the least number which, when divided by 52, leaves 33 as the remainder, and when divided
by 78 leaves 59, and when divided by 117 leaves 98 as the respective remainder ?
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Number has to be of the form:
52x + 33 & 117y + 98
or
78x+59 & 117y + 98
Following any of the two conditions, a number which satisfies both condition can be found. All we need to do then is to check whether it satisfies the third condition too.
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