vikram_k51 Posted January 6, 2009 Share Posted January 6, 2009 If n is a positive integer and x does not equal zero, is x^n > x^(n+1)? 1) x 2) n is even. Quote Link to comment Share on other sites More sharing options...
12rk34 Posted January 6, 2009 Share Posted January 6, 2009 (1) x (a) 0 x^(n+1) --- (P) (b) x (i) if n is even, x^n > x^(n+1) (ii) if n is odd, x^n (2) n is even, there are four situations, (a) x = 1, then x^n = x^(n+1) (b) x > 1, then x^n © 0 x^(n+1) ---(Q) (d) if x x^(n+1) ----® INSUFFICIENT Combining both, if x x^n > x^(n+1) SUFFICIENT Hence C. :) Quote Link to comment Share on other sites More sharing options...
buskool Posted January 6, 2009 Share Posted January 6, 2009 Agree C. Quote Link to comment Share on other sites More sharing options...
lizishao Posted January 7, 2009 Share Posted January 7, 2009 IMO C statement 1 alone is insufficient: if X statement 2 alone is insufficient: if x>1, x^n Both statement 1 & 2 are sufficient: if 0x^(n+1) if xx^(n+1) Quote Link to comment Share on other sites More sharing options...
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