Gprep Question

[kool_sunny]

if X is positive which of the following could be the correct ordering of 1/x, 2x and x^2.

 

I. x^2

 

II. x^2

 

III. 2x

 

a) None

b) I only

c) III only

d) I and II only

e) All

 

I cant get how condition II is possible??:hmm:

[12rk34]

I. x^2 4

 

II. x^2 4

 

III. 2x 4

Hence A :)

[kool_sunny]

I. x^2 4

 

II. x^2 4

 

III. 2x 4

Hence A :)

 

What if x=1/2

 

Then I) is possible

(1/2)^2

=> 1/4

 

But OA says that condition II is also true...

Thats what am looking for....:(

[12rk34]

KOOL,

If x is +ve and the given conditon does not hold good for all +ve values of x, it should be treated as INCORRECT. But it seems the question asks 'could be true' (i.e. true at least for one value of x) and not 'must be true' (i.e. true for all x).

Statement I and II will be true for x=1/2.

Such type of questions (involving could be/must be true) are normally asked in verbal and not in quantitative.

What's the OA ?

[kool_sunny]

KOOL,

If x is +ve and the given conditon does not hold good for all +ve values of x, it should be treated as INCORRECT. But it seems the question asks 'could be true' (i.e. true at least for one value of x) and not 'must be true' (i.e. true for all x).

Statement I and II will be true for x=1/2.

Such type of questions (involving could be/must be true) are normally asked in verbal and not in quantitative.

What's the OA ?

 

Value "1/2" doesnt prove condition II....:(

OA is D

[12rk34]

Sorry for the mistake.

Let us consider statement II,

x^2

=> x^3 1/2

=> x 1/√2

=>1/√2

So if we choose x= √3 /2 it will satisfy this equation, since

x^2 3/4

Hence statement II is true for x = √3 /2

So statements I and II qualify for 'could be true'.

Hence D. :)