ndcruz Posted March 19, 2009 Share Posted March 19, 2009 How many square feet of cement would be needed for a 7 foot wide continual sidewalk around the outside edge of a 60 foot by 90 foot corner lot? (a)1050 sq ft (b)1099 sq ft ©420 sq ft (d)630 sq ft Quote Link to comment Share on other sites More sharing options...
MBAchase Posted March 20, 2009 Share Posted March 20, 2009 How many square feet of cement would be needed for a 7 foot wide continual sidewalk around the outside edge of a 60 foot by 90 foot corner lot? (a)1050 sq ft (b)1099 sq ft ©420 sq ft (d)630 sq ft solution: I think typo error as area of walk ( 60 +2*7) * (90 +2*7) - 60*90 =2296 where as here is no option with this choice may be it's taken as ( 60 +7) * (90 +7) - 60*90 =1099 which is option B Quote Link to comment Share on other sites More sharing options...
rajatmeh Posted March 20, 2009 Share Posted March 20, 2009 I also got 2296, which is not there in answer choice. Quote Link to comment Share on other sites More sharing options...
hardikrs Posted March 20, 2009 Share Posted March 20, 2009 I got 1099 Rajat - the sidwalk is 7ft. wide from both edge 60/90ft. one edge si 60 ft. long and otehr is 90ft. so area -- (60+7)*7 + 90*7 60+7 -- "7" is the corner of 60 and 90 edge. Quote Link to comment Share on other sites More sharing options...
rajatmeh Posted March 20, 2009 Share Posted March 20, 2009 I got 1099 Rajat - the sidwalk is 7ft. wide from both edge 60/90ft. one edge si 60 ft. long and otehr is 90ft. so area -- (60+7)*7 + 90*7 60+7 -- "7" is the corner of 60 and 90 edge. I'm not able to visualize the corner, is it possible to draw here? Quote Link to comment Share on other sites More sharing options...
paul2432 Posted March 20, 2009 Share Posted March 20, 2009 I'm not able to visualize the corner, is it possible to draw here? Draw a 60x90 rectangle. Then draw a 60x7 rectangle on the 60ft side and a 90x7 rectangle on the 90ft side. At the corner there will be a 7x7 square. Note that the sidewalk does not cover all four sides. It only covers two sides. (the other two sides would adjoin the adjacent houses). Paul Quote Link to comment Share on other sites More sharing options...
hardikrs Posted March 20, 2009 Share Posted March 20, 2009 || ||60 ||_________90 |__________ Quote Link to comment Share on other sites More sharing options...
rajatmeh Posted March 20, 2009 Share Posted March 20, 2009 Thanks a lot Paul and Hardik Quote Link to comment Share on other sites More sharing options...
ricks2 Posted March 23, 2009 Share Posted March 23, 2009 Hi I might be taking it too far...but if we strictly go by the Question..should we not assume the presence of a Quarter circle at the corner instead of a square of 7*7..remeber "7 foot wide continual".. please do share your views.. Quote Link to comment Share on other sites More sharing options...
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