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paul2432

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paul2432 last won the day on July 27 2010

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  1. I agree wtih kamakshi. For me at least it is easier to solve these this way: Start wtih 100 people 50 take yoga. Of these 28% or 14 have heart attacks. 50 take the medicine. Of these 30% or 15 have heart attacks. Hence probability that a person that has a heart attack took yogo is is 14/29. DWarrior: If you apply your solution to the medicine you get 0.375. (0.5*0.3/0.4). Clearly since everyone takes yogo or the medicine the two should add to one. That they don't shows your solution is incorrect. The problem with your method is that P(heart attack) is not 0.4. That is the probability assuming no treatment, but everyone does one of the treatments. The probability of a heart attack is a weighted average of the probability after the two treatments. P(heart attack) = 0.5x0.28 + 0.5x0.3 = 0.29 If you use P(HA) = 0.29 you get the same answer as Kamakshi. Paul
  2. 1) Yes 2) No 3) Yes Re (3) you can't bring anything into the exam area, so it will do no good to bring the codes with you.
  3. paul2432

    PPGRE Q's

    Q1: If n is a multiple of d then n=ad. The multiples of d Q2: I get Seven. The fourth Tuesday of the month could be any of the 22nd through the 28th depending on when the first Tuesday of the month falls. Q3: The number of rubies must be divisible by both 6 and 8 for the ratios to be possible. Hence the smallest number of rubies possible is 24. If there are 24 rubies, then there are 20 diamonds and 9 emeralds for a total of 53. Paul
  4. paul2432

    embarrassed

    Here is another way. Compare both to 100021 x 90021 A is 189 x 90021 more B is 189 x 100021 more B is clearly bigger. Paul
  5. As n gets large (100 is large), then a binomial distribution is approximately a normal distribution with mean np and standard deviation [np(1-p)]1/2 In this case the mean is 100 x 0.5 = 50, and the SD is [(100)(0.5)(1-0.5)]1/2 = 5 Hence 60 is two SDs above the mean. The probability of two SDs above the mean or more is about 2.5%. Binomial distribution - Wikipedia, the free encyclopedia That said, I don't think the GRE asks questions that require knowing approximations of the binomial distribution. If it did ask this question the answer choices would be so that the answer would be fairly obvious with a little thought (e.g. all answers but one above 50%). Paul
  6. I've never seen ETS present the x-y axes without an "O" at the origin. The GRE Practice book gives some guidance on what can be assumed in figures (see page 9). http://ets.org/s/gre/pdf/gre_practice_book.pdf I strongly recommend reading through this as well as the GRE Math Guide. Paul
  7. Download Powerprep from the GRE website and do all the practice problems and sample tests. The problems there are the most realistic you will find. It sounds to me like you are favoring brute force solutions to problems where an elegant solution may be possible. If you "see" the fast way to do a problem you can often solve it in seconds where it might otherwise take several minutes. This is particularly true of the quantitative comparison problems where an exact solution is often not necessary (or even possible). The bad news is that this type of intuition is not something that can easily be developed overnight. On the other hand, you may just lack the confidence to select an answer without fully vetting its correctness. Good luck on your exam. Paul
  8. Q1: (A). They hypotenuse of a right triangle is always longer than either of the legs. The other information is irrelavent. Q2: Agree with (B) Q3: (B). A must be 2 or 3. If it was 1, then D would also be 1 violating the condition that the letters represent different numbers. If A is 4 or more than the product would be a 4 digit number. B must then be less than 5. If it were more than 5, then the thousands digit of the product would not be the same as the units digit. Q5: © I assume this refers to the graph with the 50 degree angles. The third angle of the small right most triangle is 80 degrees (three angles on a line add up to 180). Thus x+80+50=180 (three angles of a triangle add up to 180). Therefoer x=50. Q6: Question doesn't make sense. Paul
  9. (A) Something/someone X may Y. B, C and E are clearly opposite in tone and so can immediately be eliminated. D does not quite fit. It is more like someone illustrious may be lauded rather than laud someone else. Paul
  10. The answer is 8C3. Integers less than 10,000 : GMAT Problem Solving (PS) Paul
  11. I can think of two reasons: 1) Canada has fewer universities 2) Canada has colder winters which may not appeal to some I have no idea if these are the actual reasons. Paul
  12. ETS 10th was helpful. It is mostly problems without explanations which worked for me. When I did make a mistake I was always able to figure it out. In fact, not having the explanation handed to me was probably beneficial. I've found a lot of the other material was occasionally useful (Barron's, Kaplan), but often contained questions that I felt were flawed. For example, some of the Data Interpretation questions, the graphs were too small and the answer choices to close together to be able to choose the correct answer. (for example, the tick marks might be in increments of 25, but the answer choices might be only 5 apart). ETS problems never had this issue. Paul
  13. paul2432

    Number Theory

    Small correction. A number is divisible by 8 if its last three digits are divisible by 8, not if the sum of the last three digits are divisible by 8. Paul
  14. Do what works best for you. I read the passage in detail, and then answer the questions. That may or may not work best for you. I don't recommend answering questions without having read the entire passage, and read in detail at least the part that pertains to the question. Whether you read the question before the passage is up to you. Paul
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