se77en11 Posted May 9, 2006 Share Posted May 9, 2006 The sum of the first 50 positive even integers is 2550. what is the sum of the even integers from 102 to 200 inclusive? Quote Link to comment Share on other sites More sharing options...
manish8109 Posted May 9, 2006 Share Posted May 9, 2006 to find 102+104+106+------+200 200=102+(n-1)2 as d=2 200 =102+2n-2 2n= 100 n=50 terms Sum of terms= 50/2[ 2*102+ (50-1)2] =25*302 =7550(ANS) Quote Link to comment Share on other sites More sharing options...
sdasar Posted May 9, 2006 Share Posted May 9, 2006 Actually the stem is helping the addition. 102 + 104 +...+ 200 = 100 + 2 + 100 + 4 + 100 +6 .... 100+ 100 = 50 * 100 + sum of first 50 even positive integers = 5000 + 2550 = 7550 Quote Link to comment Share on other sites More sharing options...
jjaacc Posted May 14, 2006 Share Posted May 14, 2006 Thanks manish & sdasar....good explanations Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.