shud

..Gosh!!.. One of my another notes says ... Distinguish between X and Y (2 very different items, distinguished, say red and green colors) Distinguish X from Y (Two pretty similar items, say original paintings from fake ones) I think it is incorrect. Can anybody confirm ??

I came across my notes . It says use distinguish between X and Y - for similar objects and distinguish X from Y - for any objects Going by this A is better

1. 4c2*5c1 +5c2*4c1 =70 2. 6!+ 6!/2! 3. Total = 1*26*10*10*10*10 with zero at all the place = 1*26*1*1*1*1 Hence net = 1*26(9*9*9*9) 4. 50+65+50 +79+80

1) The two surgeons disagree with each other more than either does with the pathologist 2) Either of the parties have enough support to form a government. 1) Neither candidate is having an easy time with the press 2)Neither of the candidates are really expressing their own views Few More . I hope we all know 1) One of every ten rotors was found defective 2) He is one of those people who just don’t take “no” for an answer 3)The sports car turned out to be one of the most successful products that were ever manufactured in this country on participles 1)Speaking of politics, the elections have been postponed. 2)Considering the hour, it is surprising that he arrived at all. Do you think that all the sentences are correct?

IMO B B does for both. A and E addresses only one of them.

Both are participles. Most common participles are -ed and -ing . both can be used in conjunction to modify the noun. Read this http://owl.english.purdue.edu/handouts/grammar/g_verbals.html

I agree many of the 100 billion other galaxies is a noun phrase so cannot stand alone as it has no verb. actually if you supress the unwanted modifiers it says"and many of the 100 billion other galaxies " estimated to exist is adjective used for galaxies.

I got my mistake.Thanks!

xxy = 9*1*8 no of ways of arranging this = 3c2 = 3 total = 3*9*1*8 =216

I don't think that above is correct putting the first into correct and rest into incorrect = 1*2*1*1 After you have put first one , you are left three envelop. similarly after you have put second one, you are left with 2 envelop only so for third and fourth no of ways would 1 and 1.

I prefer B. But I don't know what to look for when question contains ";" or ":" Can somebody throw some light on this.

E is good. C seems like vehicle is being compared with gasoline. Those is required to have proper comparison.

Good Question. I got B. I thought its between B and E. (A) on playing, even though he had injuries that recurred over and over again, always hoping to return back - too wordy. the modifier phrase after comma is far too lengthy (B) playing, in spite of recurrent injuries, always hoping to return - best . Short and concise © playing, though injured over and over, and he was always hoping to return back - supressing the phrase we get ...continued playing and he was always hoping ..sounds awkward- Non-parallel structure. (D) on playing, even with injuries that recurred, and always hoped to return - - playing and he always hoped ..Non parallel (E) to play, despite recurring injuries, hoping that the return - looks ok at first continued to play, hoping ... But that the return to his Makes it awkward

1.7 If its worst day you have to take out all left-handed first before you get one right-handed gloves. Only when you take out all the left-handed ( which is 6) and then 1 more to be sure that right-handed is also taken out, you can claim that you have one right hannded. 2.answer should be B x=2y y=z-2 x'= x+3 = 2(z-2) +3 z' = z+3 I - nothing can be said. Incorrect II = correct, as we added 3 to both III = let say x' = z' we get z= 4 . so for z=4 both are equal not longer. Incorrect

Method 1 CIII C =Probability of putting first letter into correct envelop =1/4 I = Probability of putting second letter into incorrect envelop =2/3 I = Probability of putting third letter into incorrect envelop =1/2 I = Probability of putting fourth letter into incorrect envelop =1 CIII = 1/12 similarly for ICII = 1/8 and IICI = IIIC = 1/4 so prob = 1/12 +1/8+1/4 +1/4 = 1/3 method 2 prob of arranging CIII = 4c1 =4 prob = 4.1/12 = 1/3