vknittala

yes you are right since 16 is too small we have to use 2^8 that is the next number in the cycle. Thanks

Excellant! Thanks

Which is bigger? A) 100210*90021 B) 100021*90210 Answer is B, Can anyone explain the trick here? Thanks:)

Hey!!! Its not the exponent divided by 17 but its the 2^8 Thanks

obese :: fat :: strong :: cadaverous :: emancipated :: square :: c I am feeling the answer is d, but the answer is c why???

Hey Rumen could you please be more detailed!!! Thanks

Is the answer 175%? Thanks

Great!!! Thanks

What is the difference in the degree measures of the angles formed by the hour hand and the minute hand of a clock at 12:35 and 12:36?:) A) 1deg B) 5deg C) 5.5deg D) 6deg E) 30deg Thanks

Rumen then how is 1^2 = +/-1(I mean square of a number has to positive). Thanks

Thanks Rumen!!! 3Q) I have calculated just for the consecutive numbers and that to for only positive, so my scope was narrow. 4Q) I understood you approach but do you mean (1)^1/2 is +/- 1?? I mean in ETS its say only +1 for (1)^1/2(wehn you use the symbol) and if its asked as square root of 1 then it its +/-1 Thanks

Yogi do you mean 0 is a positive integer too in ETS?? :) Thanks

Rumen how did you get this 1^2=+/-1 ? Q5 X>0, X!=1 so X=1 sqrt1=+/-1 , 1^2=+/-1 so D) In ETS (1)^1/2 = +1 only, if not = +-1. 3Q) I am getting C Thanks

Thanks Rumen, I forgot 15+4. Then that particular approach is wrong I guess becasue its exceeding 10. By thge way do we have to write 1 as a mulitple too...any idea??? Thanks

1Q) 3+4, 3+8, 3+12, 3+16 6+4, 6+8, 6+12, 9+4, 9+8, 12+4 So 10 numbers Thanks

1q) Take two or three numbers and try (for eg: n = -1, -2, -3...0, etc and 1, 2, 3..etc and even fraction also) you will come to know a>b Thanks

Ashhad you are confusing the questions, so please write more clearly. Thanks

As number is even number, consider the total of 3 digit number that can be formed with 0, 2, 4 and 6 at unit place. Numbers with 0 at units place = 6 X 5 X 1 = 30 (1=>selecting zero from zero in 1c1 ways, and 6 => means selecting the 10th place from the remaining 6 numbers in 6c1, and 5 => means selcting the 100th place from the remaining 5 numbers in 5c1 ways) Numbers with 2 at units place = 5 X 5 X 1 = 25 (1=>selecting zero from 2 in 1c1 ways, and 5 => means selecting the 100th place from the remaining 5 numbers in 5c1,"HERE no zero" and 5 => means selcting the 10th place from the remaining 5 numbers in 5c1 ways "HERE ZERO IS POSSIBLE") Numbers with 4 at units place = 5 X 5 X 1 = 25 (1=>selecting zero from 4 in 1c1 ways, and 5 => means selecting the 100th place from the remaining 5 numbers in 5c1,"HERE no zero" and 5 => means selcting the 10th place from the remaining 5 numbers in 5c1 ways "HERE ZERO IS POSSIBLE") Numbers with 6 at units place = 5 X 5 X 1 = 25 (1=>selecting zero from 6 in 1c1 ways, and 5 => means selecting the 100th place from the remaining 5 numbers in 5c1,"HERE no zero" and 5 => means selcting the 10th place from the remaining 5 numbers in 5c1 ways "HERE ZERO IS POSSIBLE") Thus, total of 3 digit even number = 30+25+25+25 = 105 Thanks

I got it !!! Probably this is a GMAT problem which is totally different form GRE. Thanks

Hey Micknugget!!! For the same problem when do we chosse A, B, and D??? I mean in the answer choices. Thanks

Excellant Rumen!! Thanks

Hey Micknugget!!! Though we prove that "a" is a multiple of 3 and so do "b"... The question here is which is bigger or equal or cannot be determined. For that we have to know the value of the "a" and "b" to compare. So now how do you find whether 3(k+z) > May be I missed something somewhere then please let know, I appreciate your help.:) Thanks

Dear Friends!!! Plz someone tell me where am I lost! Thanks

Hey Vinay!!! Good luck and you will do it! Thanks

:) Hey Fortune!!! I understood your approach and looks convincing. Could you please tell me where am I lost :( Thanks