Hey, I just looked at another forum and it said that 0.56 is the correct answer, but apparently it says 1.629 in the book. Here is how I did it:
the goal freezing point is -0.52 to make the soln isotonic.
the fp of 2.5% procaine hcl is 0.122*2.5= 0.305
so -0.52--0.305= -0.215--> how much NaCl we must add to make it isotonic
with proportions,
1% NaCl/x = -0.58/-0.215
x= 0.371% NaCl needed to make soln isotonic
0.371% x 150cc= 0.56g NaCl
what is the answer? I kind of know how to do it, but I want to make sure I am getting the right answer.
I got 0.56g sodium chloride. If it is the right answer I will explain it.
You need to do alligations for this problem:
78| | 28
| 38 |
10| | 40
68 total
so basically you need 28 parts of the 78%, and 40 parts of the 10% to get 68 parts of the 38%.
28mL/68mL x 50mL= 20.6mL of the 78%
40mL/68mL x 50mL= 29.4mL of the 10%
Hope this is right.
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I'm sure you probably do not need this by now, but for other people:
If 400mg is in 500 mL, and there are 3 doses per day, then:
1mL/25mg x 400mg/dose x 3 doses= 48mL= 2.4 ampules per day
Usually each dose is in seperate 50mL bags, therefore if 50mL is given over 0.5 hours, then the answer is 100mL/hr regardless of how much Pen is in each bag.
I tried that calculation, and I came up with 0.8mg/day as well. the only possible way I can think of getting 1.6 is if they thought there were 10 drops/mL, but that does not make any sense. Is it possible that the book is wrong?