onthego

I agree. I think by non-zero digits, it is referring to the decimal part so it should be seven.

36,000 + 9x + x = 441,000 x=40,500 => 9x = 364,500 so C

I am not sure but will 1 and 6 be considered as factors of 6?

3) I am not sure if this d = 1 / 2^3 * 5^7 means d = 1 /( 2^3 * 5^7) or this means d = 5^7/ 2^3? If its the first one. 1/(2^3 * 5^3 * 5^4) 1/(10^3*5^4) multiplying num and den by 10^4 10^4/(10^7*5^4) (10/5)^4/(10^7) or 2^4/10^7 so it has 7 decimal digits 4) Finding LCM of 90, 196 and 300 => 9 * 25 * 49 * 4 => 9 * 49 * 100 so 600 is not a factor

1) y = mx + s (where m is the slope and s is constant) y = 4x + s 0 = 4(0) + s (since this passes through origin) => s=0 y=4x is the equation substituting values of 2 coordinates in this eq. c=4(1) ----eq1 2=4(d) => d = 1/2 ----eq2 dividing eq1 and eq2 c/d=8 2) Let rate in R = x => rate in P = .75x ----1 Let rate in G = y => rate in P = .9y ------2 equating 1 n 2 .75x=.9y or x = 1.2 y so rate in Hotel R is 20% more than G

This expression includes a sum of geometric progression. For a G.P. a0, a1, ... , an where a0 * r = a1, a1 * r = a2, ... then Sn = a0(1-r^n)/(1-r) if r or Sn = a0(r^n-1)/(r-1) if r>1 => 2 + 2 + 2^2 + 2^3 + 2^4 + 2^5 + 2^6 + 2^7 + 2^8 = => 2 + [2 + 2^2 + 2^3 + 2^4 + 2^5 + 2^6 + 2^7 + 2^8] => 2+[2(2^8-1)/2-1] => 2+2(2^8 - 1) => 2 + 2^9 -2 => 2^ 9 I hope this helps.

Thanks and Congs.

Thanks for clarifying though...I was wondering if I am missing something.

I think its E ..coz government is trying to reduce urban unemployment by processing crops locally but actually unemployment is increasing in urban area since farmers are selling their land and moving to cities due to lack of a profitable crop.

Lets choose the largest 3 digit number since the problem talks abt greatest possible product. 999*999 (1000-1) (1000-1) = 1,000,000 - 2000 +1 so this would be closest to 1,000,000

4pi=pi (d1*d1)/4 ---(1) 100pi= pi(d2*d2)/4 ---(2) dividing 1 and 2 1/25=(d1*d1)/(d2*d2) 1/5=d1/d2 or d2 = 5d1

Oh Cool, thanks Retake_GMAT. So its more of an inference, huh!!

Why cant we add 2 and make it divisible by the only even prime?

I didnt understand the following - i.e., 50!*2^50 + 1 is NOT divisble by ANY prime factor less than or equal to 47 What is the determining factor for saying that this number isnt divisible by prime factor less than 47? Appreciate any help on this.