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libuser

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  • Birthday 06/07/1992

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  1. for those wondering cramya did backsolving with the answers. Once you see that the minimum answer should be 22, you disregard answers C,D, and E. Next you pick answer B. When you have 28 as the remainer, the first quotent will be 39, and 49 respectively. Add them, and divide to see if the remainder will be 4. Easy
  2. Q3. you have 3 points, imagine you substitute R and S for x and y on the cartesian coordinate system. Then you would have a straight line that connect those 3 points. To find the missing point you use the formula of slope: (y2-y1)/(x2-x1)=(y4-y3)/(x4-x3), or in our case: (100-60)/(x-24)=(60-30)/(24-6) Solve for X -> 48 It will be a lot easier if you can draw the points, and then you will see yourself. It took me less than a min to solve the equation and solve this one.
  3. When Inez and Fernando purchased a property for $20,000, Fernando contributed 1/3 the amount contributed by Inez for the purchase. If they sold the property for $40,000 and shared this amount in proportion to their respective contributions how much was Fernando's share? (A) $5,000 (B) $10,000 © $13,333 (D) $20,000 (E) $26,666
  4. If S is a set of integers and 5 is in S, is every multiple of 5 in S? 1. If x is in S, then x+5 is in S 2. If x is in S, then x-5 is in S OA later. : )
  5. Here is a quick one: A trustee invested a total of $100,000, more than half of which was invested at 6% simple annual interest and the rest of which was invested at 8% simple annual interest. What amount was invested at 8%? 1. The total annual income on the investment was $6800 2. If twice as much had been invested at 8% and the rest at 6%, the total annual income on the investment would have been increased by $800.
  6. I think I got it though, i was tired and was not straight last night, but I think the shortest solution is: 27 1/8 - 27 = 1/8 45 3/4 - 45 1/4 = 1/2 1/8 x 200 + 1/2 x 100 = 75
  7. sorry guys. missed the values. all there now : )
  8. nopes that is the exact question from Veritas test. : )
  9. Here is another interesting problem that I have no idea on how to approach: A manufacturer can save x dollars per unit in production costs by overproducing in certain seasons. If storage costs for the excess are y dollars per unit per day (x>y), which of the following expresses the maximum number of days that n excess units can be stored before the storage costs exceed the savings on the excess units? A) x - y B) (x-y)n C) x/y D) xn/y E) x/yn OA will be given later :)
  10. A person purchased 200 shares of stock X priced at $27 and 1/8th per share and 100 shares of stock Y priced at $45 and 3/4 per share. The next day the prices per share were $27 and $45 and 1/4, respectively. If these figures represent dollar values, what was the one day decrease in the total price of the 300 shares? (A) $75.00 (B) $62.50 © $37.50 (D) $25.00 (E) $12.50 OA later
  11. 1.As recently as 1950, tuberculosis was never curable unless sequestered in sanitariums; today, the drug Isoniazid has made such treatment obsolete. (A) unless sequestered (B) without sequestering © without being sequestered (D) unless it was sequestered(E) (E) unless patients were sequestered
  12. OA is E man. I have done that question before, and here is the explanation: statement (1) you need to pick numbers such that x^2 + y^2 > z^2, per this statement. first, pick a completely random set of numbers that does this: how about x = 1, y = 1, z = 0 these numbers give a YES answer to the prompt question, since 1^4 + 1^4 is indeed greater than 0^4. now remember: your goal is to prove that the statement is INSUFFICIENT. this means that we have to try for a 'no' answer. this means that we have to make z^4 as big as possible, while still obeying the criterion x^2 + y^2 > z^2. unfortunately, this isn't as easy to do as it was last time; we can't just make z a huge negative number, because z^2 would then still be a giant positive number (thwarting our efforts at obeying the criterion). so, we have to finesse this one a bit, but the deal is still to make z as big as possible while still obeying the criterion. let's let x and y randomly be 3 and 3. then x^2 + y^2 = 18. we need z^2 to be less than this, but still as big as possible. so let's let z = 4 (so that z^2 = 16, which is pretty close).** with these numbers, x^4 + y^4 = 162, which is much less than z^4 = 256. therefore, NO to the prompt question, so, insufficient. statement (2) you need to pick numbers such that x + y > z, per this statement. first, pick a completely random set of numbers that does this: how about x = 1, y = 1, z = 0. these numbers give a YES answer to the prompt question, since 1^4 + 1^4 is indeed greater than 0^4. now remember: your goal is to prove that the statement is INSUFFICIENT. this means that we have to try for a 'no' answer. this means that we have to make z^4 as big as possible, while still obeying the criterion x + y > z. fortunately, this is somewhat simple to do: just make z a big negative number. try x = 1, y = 1, z = -100 in this case, x + y > z (satisfying statement two), but x^4 + y^4 is clearly less than z^4, so, NO to the prompt question. insufficient. answer = e.
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