nh8404052006

IMO the answer should be A: B: if it is placed in a European city instead of an American city is awkward B, C and D: the use of will may not be necessary, I prefer simple presnt tense C: one has no clear referent

A, B and C have 5 donuts to share. If any one of them can be given any whole number of donuts from 0 to 5, in how many different ways can the donuts be distributed? Please explain thank OA: TM_M897

The radius of the smaller circle is 2 and radius of bigger circle is 5. If the tangent to the smaller circle intersects the bigger circle at ‘P’ and ‘Q’, then find the length of PR? The diagram is can be found in the question 2 of the following link http://www.www.urch.com/forums/gre-math/103203-somemore-october-quant-problems.html please explain, thank No OA available TM_M807

For Statement (1) if n = 1, then 2^n = 2 and the remainder of 2 / 3 is 2 ==>statement I may NOT be true. For statement (II) if 3^n= (-3)^n, then n must be even i.e. n = 0, 2, 4, 6, 8, …. When n = 0, 2 ^ n = 1 and the remainder of 1/ 3 is 1. when n is other even numbers, 2^n is 4, 16, 64, 256, …=4^m. Note that the remainder of (4^m /3 )must be 1. The reason is as follows: 4*4=(3+1)(3+1)=3*3+3*1+1*3+1*1==>The blue portion is a multiple of 3==>3p+1 so,,4^2*4=(3p+1)*4=(3p+1)(3+1)==>Repeat the exercise as above ==>3r+1==>we can write 4^m =3x+1 for any m, x belongs to Integer. so, if 4^m is divided by 3, the remainder must be 1 ==> statement II must be true. For statement III. Sqrt(2^n ) belongs to integers ==> n must be even. ==> statement III must be true. (The reason is the same as given above) OA : E

If x is a positive integer, is the remainder 0 when [(3^x) + 1]/10? (1) x = 3n + 2, where n is a positive integer. (2) x > 4 Please explain, thank OA: TM_M545

Is ¦x - y¦>¦x - z¦? (1) ¦y¦>¦z¦ (2) x Please explain, thank OA: TM_M537

What is the value of │x + 7│? (1) │x + 3│= 14 (2) (x + 2)^2 = 169 Please explain, thank IMO: TM_M504 Please note there was a typo in the question and the typo has been corrected. Sorry for the confusion.

If (x + a)(x + b) = x^2 + cx + 17 and a, b, and x are integers, is a > c? 1. ab > 0 2. a Please explain, thank No OA available TM_M502

IMO C Find B / (B+G) From statement 1, B + G = 840, Two unknowns in one equation, thus insuficient From Statement 2. ==> 72%B +80%G = 75% (B+G), it is still impossible to determine B / (B+G) But both statement together, we have two equations and two unknown, thus, sufficient. Unless, I miss something, I do not think B is right.

If A men and B women can do a piece of work in X days together, How long would it take to accomplish the task with M men and N women? Please explain, thank No OA available TM_M478

5 boys and 5 girls stand in a line, what is the probability that no two girls stand next to each other? Please explain, thank No OA available TM_M473

A computer program is to generate a 4–unit password code from 0 to 9, what is the probability that the code does not start with 0 and no repetition is allowed.? (i.e. 1111 is a not legitimate password code; while 1209 is valid.) Please explain,thank No OA available TM_M415

A={1,2,3,4,5,6} and B={1,2,3,4,5,6}. If we pick one number from each set, what is the probability that (a) one number is bigger than the other? (b) one number is bigger than the other by 2? Please explain, thank no OA available TM_M414

First, assume all lights are the same, the total number of arrangement is 13! Now, 4 R belongs to the same class, 3 blue belongs to the same class, 4Y belongs to the same class, and 2 green belongs to the same class. Thus, the number pf arrangement is 13!/(4!3!4!2!) which is not 900,900 Please go to the following link for the math concept, look for what Stuart Kovinsky say. Combinatorics... It would be a much more interesting question if there are 15 sockets rather than 13 sockets. Is there anyone who want to try? Hope it help.

There are 6 groups in a room. Each group consists of 3 men. How many handshakes will there be if each man only shakes hands with people who are outside his group? Please explain, thank No OA available TM_M424