Q1:
S= 2*L
S= 3*P
when P completes a work in 12 hours
makes S can complete it is 4 hours
implies that L can get it done in 8 hours
hence in 6 hours L would have completed 3/4th of the work.
Q2:
the given relation between Abby/Beth & Carol can be depicted in the following format with time in minutes taken by each of them for 1 unit of work.
Person ------>time(in mins) -------->units of work
B -------------------->60-------------> 1
A -------------------->30-------------> 3
implies that A --------> 10-------------> 1
C -------------------->60-------------> 1
B -------------------->120------------> 1/3
implies that B --------->120*3---------> 1
hence when C completes a job in 1 hr (60 mins)
implies that B takes 120*3 mins for the same work
hence A can get it done in 120*3/6 = 60 mins -> 1 hour
Q3:
for one house the number of days relation between A:B:C can be written as
6A = 8 B = 12 C
the total work is 3 houses , => 18A = 24B = 36C
A completed 8 days of work , hence the remaining work = 10 days work .
the remaining work in terms of B(no of days) = 24 x 10/18 = 40/3 (days of work )
B completed 6 days of work , hence the remaining work days = 40/3 - 6 = 22/3 days
Remaining work in terms of C = (36 x 22/3)/24 = 11 days.
hence C needs to do 11 days of work to complete the job.
