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In addition to credit and income requirements, many landlords also require that, before or at the time of signing a residential lease, each prospective renter pay not only the first month and last month's rent and a security deposit that is usually equal to one month's rent. A pay not only the first month and last month's rent and B pays not only the first month and last month's rent and C pays not only the first month and last month's rent, but also D will pay not only the first and last month's rent, but also E pay not only the first and last month's rent, but also can someone please explain why its not C?

IMO E here is why A. that government officials agree to have the area razed. "requiring that" is unidiomatic B. that government officials agree for to have the area razed. agree for is unidiomatic C. the agreeing by government officials to have the area razed. should be the agreement of D. government officials agreeing to have the area razed. should be to agree E. government officials to agree to have the area razed.

State revenues from the corporate income tax are seriously threatened by the new trend towards decentralization of corporate headquarters. Many of the companies leaving the city and its extensive public transportation system are finding it necessary to import costly executive helicopters to transport personnel to and from isolated locations in the suburbs. Because money spent on these helicopters is deductible from gross corporate income as an expense of doing business, such companies will thus pay lower taxes to the state. We must apply appropriate economic sanctions to avoid the loss of these much-needed tax revenues. Which of the following, if true, most weakens the reasoning on which the argument depends? a. Higher personnel transport costs are offset by other savings at the new corporate headquarters. b. Tax revenues lost from corporations leaving the state will exceed those gained if sanctions are imposed c. Increased taxes are paid by helicopter manufacturers as a result of booming business. d. Business executives prefer the convenience of rapid helicopter travel. e. There are other economic difficulties for cities caused by corporate relocations to suburbs. I don't get why. In C we don't know if the taxes are going to the state. In B we know that the state will lose more taxes by having corporations leave the state. any thoughts?

wow! this is a tough one. Here is how I do it. There are three proportions and three unknowns - the original weight, the amount of water added, and the final weight. so three equations will lead to three unknowns. here is how I do it. Let x = original volume Let Y = final volume Let w = volume of watter added Your three equations are 550 = 7/18*y-1/6*x 200=6/18*y-2/6*x w=5/18*y-3/6*x

if pq>4, is p>1 A 2 B 0 I figured this one out using #s. Can someone show me a better way to solve it?

imo B since 450 is 3^2*5^2*2 and n is to the power of 3, therefore, 450*y must be at least some number to the power of 3. therefore, 459*y must be at least 3^3*5^3*2^3 therefore y must be ate least 3*2*2^2

B is enough. if 36 subscribed to at least 1, and 17 subscribed to at least 2, then 36-17 only 1.

OA is A any negative sloping line will go through the 2nd and 4th quadrant. any positive sloping line will go through the 1st and 3rd quadrant. note however that it is possible for a positive sloping line to intersect the 2nd or 4th, but not both, and it is possible for a negative sloping line to intersect the 1st and 3rd, but not both. my advice: if you want to visualise this, draw the following lines: 1. y = 1*x + 6 [intersects 1st and 2nd and 3rd]. 2. y = 1*x + 0 [intersects 1st and 3rd]. 3. y = 1*x - 6 [intersects 1st, 3rd and 4th] 4. y = -1*x + 6 [intersects 1st, 2nd, and 4th] 5. y = -1*x + 0 [intersects 2nd, and 4th] 6. y = -1*x - 6 [intersects 2nd, 3nd, and 4th].

OA is D here is how: 1. lets first pick apart 2*√(63): 63 = 9* 7 thus 2*√(63) = 2*√(9*7)= 2*√(9)*sqrt(7) = 2*3*√(7) 2. lets pick apart 2/(8+3√7) by getting rid of the ugly denominator. 2/(8+3√7)*(8-3√7)/(8-3√7) = [2*8-2*3*√7]/[8*8 -3*3*√7*√7] = [2*8-2*3*√7]/[64 -9*7]=[2*8-2*3*√7]/[64 -63]=[2*8-2*3*√7]/[1]=[2*8-2*3*√7] thus we get our original equation to be √[2*3*√7+2*8-2*3*√7]=√[+2*8]=√[16]=4

think of it this way: 1. every number can be reduced to a prime number, therefore, all you need to figure out is if [1/prime numbers ] will "end" 2. lets look through the prime numbers 1/1 = 1 1/2 = .5 1/3 = .3333.... 1/5 = .25 1/7 = .142567... 1/11 = .09090909.... 1/13 = .0769.... 1/19 = .05263.... I would venture to say that no other prime number will terminate (although I don't have a proof). Either way, you could have reduced all the denominators to their prime numbers and seen if they are terminating.

We are shown the following graph Y```````````` / |```````````. (c,d) | ````````/ | ```` / | `` / |/r_______ X r is the angle the line makes with the X axis and (c,d) are the coordinates of the point on the line The question asks "in the figure above, what is the value of r" (1) c = 2 (2) c = d Spoiler: here is what i don't get. i understand that if C = D then the angle SHOULD be 45. However, lets say that C = -2, then D = -2 and the angel would be NEGATIVE 45, or 315. So why isn't the answer C - that when we combine the two we know its 45 and not -45. My only guess is that the "picture they give you tells you its in the first quadrant and therefore 0

be careful with the first part. 0 is not an option for the first digit. therefore there are 5 possibilities for the first digit, 5 possibilities for the second (the number used for the first digit is no longer an option, but 0 is now an option) and there are 4 possibilities for the 3rd digit. Thus, total possibilities are 5*5*4 = 100 The second part is a bit trickier. The mistake they want you to make is to say that since it can be one of 6 digits, and half are even (0,2,4), that there is a 50% probability of it being even = 50% * 100 = 50. However, this does not take into account the fact that 0 cannot be the first number, which means that it has a higher probability of being the last number, which means that the probability of having an even number is grater then 50%. I like DWarrior's solution for how to solve this part of teh Q.

(please see above post) the formula is sum = average * count of odd numbers average = (first + last)/2 [not always, so know when to use this. here we can use it because the numbers are sequential by +x] count of odd numbers = RoundUp( [last number - first number + 1]/2)

yes. much easier formula step 1. realize that the average of 1, 3, 5 (which is 3) is the same as the average of 1,2,3,4,5. (which is 3). in other words, as long as i'm sequential, it doesn't make a difference if i sip every other number. You can "visualize this by seeing how every number to the left of the middle gets "canceled" by a number to the right - 2 is canceled by 4 and 1 is canceled by 5. In other words, since just like 2 is "3-1" you have 4 being "3+1", therefore when you average them, you get "(2+4)/2" = "( [3-1] + [3+1])/2 = 3 so the "+1" and the "-1" cancel. 2. know that the average of any sequence (where the numbers increase by 1) is simply the average of the first and the last number e.g. the average of (5,6,7,8,....195) is simply (5+195)/2. therefore, the average of (1,2,3,4,5,991) is = (1+991)/2 = 496 3. since we established in part 1 that the average of (1,2,3,4,5,991) is gong to be the same as the average of (1,3,5,991), and we showed in part to that the average of (1,2,3,4,5,991) is 496, therefore the average of (1,3,5,991) is 496 4. since Average = sum/count, therefore sum = average * count 5. we know that the average of (1,3,5,991) is 496 (see step 3) 6. the count of (1,3,5,991) is a bit trickier: since odd and even numbers go in pairs, lets first figure out how many numbers there are from 1 to 990. count of a sequential series (when incremented by 1) = last number - first number + 1 thus, count of all the numbers from 1 to 990 = 990-1+1 = 990. since there are half as many odd numbers, there are going to be 990/2 = 495 odd numbers from 1 to 990, which means there is going to be one more odd number from 1 to 991. Therefore, there are going to be 496 odd numbers from 1 to 991. 7 since sum = average * count (step 4) and since average = 496 (step 3) and since count = 496 (step 6) the sum = 496*496 = 246016 i verified this number in excel.

I'm with A. D changes the focus from "what needs to be done to IT" to what "YOU need to do".