Austin_TX

7C2 * (1/2)^7 = 21/128

Congratulations Ursula ! This is awesome. I would really appreciate if you can share: - what kind of problem you got fom probability/permutation/combination/standard deviation. Were those really difficult or at the same level we usually see at this forum. - did questions got easier after you 'nailed' the first few difficult questions. - also, did u ran out of time in any section? if yes did you left a few questions unanswered or guessed. Thanks.

I don't uderstand the answer to sceanrio number (1). It should not matter how small and large a set is. It is the range that should matter. I think, a set of only two numbers {1, 1000} will have higher standard deviation than a set of 10 elements {5,5,5,5,5,5,5,5,5,5}.

This question was discussed earlier on this forum, but no answer was provided by the person who posted this question. There was lot of discussion but no consensus. So here it is again: A club has a membership of 9 men and 12 women...21 people total. A 5-member committee is to be selected to attend a conference. How many committees with no more than three women be formed?

I think this question was discussed earlier in this topic, but there was no answer provided and there was lot of discusson but no agreement on answer or explanation. Here it goes again: John has 7 bananas and 3 kiwis. He needs to divide the 10 in two parcels, so there is an equal total number of fruit in either parcel and so that there is at least one kiwi in each parcel. a) 21 b) 35 c)60 d) 105 e) 120 I calculated the result to be 105. Do you guys agree? I just want to make sure if my approach and answer is correct.

Hi vknittala: I follow your logic but I don't understand when you state "5 => means selecting the 100th place from the remaining 5 numbers in 5c1". For 100th place there are 7 numbers available, why you are saying only 5 numbers available. Can you please explain. Thanks.

I think this question was discussed earlier in this topic, but there was no answer provided and there was lot of discusson but no agreement on answer or explanation. So here it is again: From the word ZEBRA how many different letter combinations can be arranged by using the foregoing letters? a) 20 b) 60 c)100 d) 120 e) 150

87 * .0000125 * x = .018 x = 16 and some fraction but if only full servings are allowed x = at least 17 servings

Is answer 17

Your answer is correct, and you explained it very well. Thanks.

Your answer is correct, and you explained it very well. Thanks.

Thirteen cards numbered through 1 through 13 are placed in an urn. If five cards are drawn at random, what is the probability that the numbers are sequential? The drawn cards may be rearranged if necessary. Answer = 1/143

If you roll 3 dices, what is the probability the numbers will add up to 6? Answer = 5/108

Is answer B ?

Is answer E ? I don't know if this is correct, but here is my analysis: Let the big countertop has side = b; area of countertop = b^2 Let the tile inlay has side = a; area of tile = a^2 The strip has width = x; which means b=a+2x Area of untiled strip= area of countertop – area of tile inlay = (b^2) – (a^2) (a^2) / ((b^2) – (a^2)) = 25/39 (a^2) / (b^2) = 25/64 a/b=5/8 we know that b= a+2x a / (a+2x) = 5/8 a = (10x)/3 Plugging in the values from answer choices x = 3/2; a = 5; b = 8; a/b = 5/8; (a^2) / ((b^2) – (a^2)) = 25/39 x = 3; a = 10; b = 16; a/b = 5/8; (a^2) / ((b^2) – (a^2)) = 25/39 x = 9/2; a = 15; b = 24; a/b = 5/8; (a^2) / ((b^2) – (a^2)) = 25/39 All of them are valid.