BLUEKNIFE

Very happy and proud... Thanks guys!....your help was very important. BK

I got it!!!! I understood now The chart shows just the amount of kind of pet VS household. So, it might be possible one house with 1 dog, 1 cat and 1 other. That is the reason because we can determine the households with at least one pet VERY tricky problem....I was thinking on it all the day!!...

You must be careful with this Quicker-Way.....check this problem: http://www.www.urch.com/forums/gre-math/126627-another-tricky-problem-math.html

The problem is when you use the "quick-way" to solve the problem, making a cross multiplication A) 2+t^3 B) 2+t^2 If we try with your numbers ( t= -1 & -2) 1) t= -1 , A=1 & B=3 , so A 2) t= -2 , A=-6 & B=6, so A Can someone explain me this??

Yeah...I did the same calculations, but according to PP the correct answer is D

Please Guys..... [ATTACH=CONFIG]5898[/ATTACH]

t is a negative integer. A) 1 / (2+t^2) B) 1 / (2+t^3)

You don't need a formula for this problem. Depreciation Machine X: 0.1V (10% of original value, 10% of V is 0.1V) Depreciation Machine Y:0.2V (10% of original value, 10% of 2V is 0.2V) If we apply a constant rate for each year: Machine X Year 0: V Year 1: V-0.1V=0.9V Year 2: 0.9V-0.1V=0.8V Year 3: 0.8V-0.1V=0.7V Machine Y Year 0: 2V Year 1: 2V-0.2V=1.8V Year 2: 1.8V-0.2V=1.6V Year 3: 1.6V-0.2V=1.4V Year 4: 1.4V-0.2V=1.2V Year 5: 1.2V-0.2V=1.0V Year 6: 1.0V-0.2V=0.8V So, 0.7V Answer B

I can't believe I was wrong on my response. This problem looks simple, but it's very tricky....If someone could explain me the logic behind of this, I really appreciate it. The ratio of men and women on a panel was 3 to 4 before one woman was replaced by a man A) The number of men on the panel B) The number of women on the panel Solution

Good point Irrational....and I agree with you. What do you think about the other problem?

Thanks for your quick response....I really appreciate that

Wow....thanks guys....but, I'm not sure about the 2nd. The book has the following explanation: 2) Let's find all the unique products by picking each number from List A, and multiplying it by each number from List B. 1x2 1x5 1x5 2 5 6 3x2 3x5 3x6 -> 6 15 18 5x2 5x5 5x6 10 25 30 The unique products are: 2,5,6,10,15,18,25 and 30, a total of 8 different numbers. Among these, the odd numbers are 5,15 and 25, a total of 3 different numbers. Probability of the product being odd is 3 out of 8, or 3/8

Hi guys....I found this problems. 1) My brother, my cousin and I were in the same class of 70 students. My brother graduated at top of the class, whereas I ranked 27th at graduation. What's probability that my cousin ranked between me and my brother? For me, the probability is 25/68; but according to the book the prob. is 25/70. What do you think? 2) List A: 1,3,5 List B: 2,5,6 If you select a number each from List A and List B above, what's the chance that the product of the two numbers selected will be an odd number? For me, the probability is 1/3; but according to the book the prob. is 3/8. What do you think?