I'll try my best Herr or Frau Amit.
[3(x + 2) + 2x] - [4(y + 2) - 3(y - 2)]
First we do our order of operations:
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Parenthesis
Exponents
M-D: multiplication and division
A-S: addition and subtraction
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So, in our equation: [3(x + 2) + 2x] - [4(y + 2) - 3(y - 2)] , we have P, M, and A-S
First tackle the parenthesis'
[3(x + 2) + 2x]
Distribute 3 to (x+2) by multiplication and end up with:
[3x+6+2x].
Same Here:[4(y + 2) - 3(y - 2)]. Distrubte 4 to (y+2) and 3 to (y-2) by multiplication and receive:
[(4y+8)-(3y-6)] But notice the negative in front of (3y-6). You should treat it as -1(3y-6) //this is where you messed up.
so distribute -1 to (3y-6) by multiplication and get:
[(4y+8)+(-3y+6)]
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Now we do addition (or subtraction) of like terms:
[3x+6+2x] 3x and 2x are like terms so add.
[5x+6]
Now [(4y+8)+(-3y+6)]: 4y and -3y are like terms, add. 8 and 6 are like terms, add.
[y+14]
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Now we do the final calculation:
[5x+6]-[y+14] : Notice you have that pesky negative infront of [y+14] again. treat it as -1(y+14)
distrubte -1 to (y+14) by multiplication
[-y-14]
add like terms
5x-y-8
If I did not explain it well, please tell me which part. or if you would like another example.
Enjoy, or don't