GiveItaGo

Hi Everyone, I'd like to thank everyone on this forum especially Erin for setting it up.. I gave a test last week and scored 720 (q48, v40), was quite relieved to have it over an done with .. although i think i should have done better in verbal. I think in the last ocuple of weeks i focused to hard on the quant because i was more scared of that and i think my verbal suffered ... anyways its always easier in retrospect... I've really glad to have it over with.. I'm from australia and don't know anyone giving the gmat around me so it was nice to have this forum , felt like i had a study group around me and other people who were going through same pain... Cheers! [clap]

1)Don't really understand what the question is asking. 2) a) aba=a this holds true if a=0 or ab=1 therefore not sufficient. c) bab = b this holds true if b=0 or ab=1 therefore not suffiencient. together they are not suffient either as a= and b=0 satifies both and a=1 and b=1 satisfies both. 3) I agree with E . As we need to have the probability of B to work that out. 4) Think its D. Although if you want to get really nit picky then its A as B does not state which monday he arrived on . He might have arrived a week late. 5) How does a satisfy it. if m=7 and n=10 then the greatest common divisor is 1 however if n=14 then it is 7. I think the answer to this is C. as the grestest common divisor will be 1 in this case.

Thanks for that solution GMAT-HELP.. i wouldn't have seen it otherwise.

Yeah i agree it has to be A.

I think its E. Vingmat, I understand the statement 1 to be : x= (y^k)*p . Because from your equation (k*y)^2 it implies that y goes into x twice x= k*y *k*y, however the question states that it can go many times. Not sure though. (i'm not that good with equations) Anyways plugging some numbers in may help. x=36, y=6 and z=12 ; this does not yeild an integer. x=36 y=6 and z=6 ; This does yeild an integer. so my guess it E.

4) We already know that the egg that is picked is defective. So we are only concerned with the defective eggs , 4 brown defectives and 6 white defectives. Thus the probability that the defective egg is brown = brown defectives/total defectives = 4/10 =2/5

Are we expected to know these formulas or is there an easier way of doing this.. or better still is a question like this not likely to come up.

Another way would be .. find the lowest common multiple of 4,6 and 8. This will equal the length of one of the three equal parts. 24 can be divided by 4,6,8. Total length of original will be 24*3 =72.

First you have to work out how much he earns per hour for overtime. overtime rate = $5.60 *1.5 = $8.4 So for every overtime hour he gets $8.40. He worked 8 hours overtime, so in total he would get $8.40 * 8 = $67.20 for his overtime hours.

Yep good idea. Thanks for that suggestion. Also typo in my solution. x=L*W x=(x-6)/2 x=18 should be x=L*W x=(x-6)/2 * 3 x=18

You can also answer this by back solving from the choices. A) if 18 were rented out. then 2 remained on the lot (20-18) and 9 were returned (18*50%). So the total trucks at the lot = remaining + returned = 2+9 =11 . So a can't be the answer. B) similary for. remaining + returned = 4+8 = 12. Thus B is the answer.

great explanations.. thanks for your efforts

Hi Chimney This is how I solved the two questions above. 1) 10^1 =100 has 2 digits 10^2 =1000 has 3 digits 10^3 =10000 has 4 digits So the pattern is that 10^n has (n+1) digits. Therefore 10^100 has (100+1) digits.Thus the answer is 101. 2) We know the area is x sq feet. Strip had length x before it was fitted around the table. The width is 3. Let the length of the table be L and width be W (which we know is 3). length of strip = 2L +2W (as the strip was put around the perimeter of the rectangle) therefore x=2L+2W x=2L +2(3) x=2L + 6 L = (x-6)/2 now we know that the area of the table is x. x=L*W x=(x-6)/2 x=18 We still need to get the length L=(18-6)/2 . answer : length is 6.

Hi David, I have a question with regards to addmission timings.. I'm planning to give my test in the middle of september (originally planned for early august .. but some major stuff has come in at work and i'm unable to give it at that date..) is this enough time to prepare for the 2nd round of addmissions. Thanks Mita

Does anyone know how close the 800Score math tests are to the real GMAT with regards to difficulty. would appreciate some feedback as i'm about to take my GMAT soon and i'm a bit worried about the Quant section