johnnyrocket

5 R-type instructions are to be executed on a 5-stage (scalar) pipelined processor. here are no dependencies among the instructions. If this same instruction sequence is executed instead on a degree-2 super-pipelined version of our processor, what speedup factor would be provided if no other changes are made? l know that a degree-2 super-pipelined system splits each stage into 2 phases so that the time required for the two phases is the same as the original clock cycle time.

5 R-type instructions are to be executed on a 5-stage (scalar) pipelined processor. There are no dependencies among the instructions. If this same instruction sequence is executed instead on a degree-2 super-pipelined version of our processor, what speedup factor would be provided if no other changes are made? A degree-2 super-pipelined system splits each stage into two phases so that the time required for the two phases is the same as the original clock cycle time.

The format of the Page Table Entries for a certain system that employs 32-bit virtual addresses and pages that are 8192 bytes in size is shown below: Bit23: Valid Bit Bit22: Modify Bit Bits 21-18: LRU Bits Bits 17-0: Frame Number - What is the maximum amount of physical memory the system could contain? My guess: We have 18 bits for the frame number. So 2^18 * 8192 bytes = 2 GB -What would be the total size in bytes of the page map table? -If an inverted page map table is used what would be its total size in bytes if the LRU field within each PTE is reduced to 3 bits?