ravsav

Hi all, Yes backsolving did help.Answer choices are : A. 2,7,7 B. 4,6,6 C. 6,5,5 and D. 8,4,4. I wanted to know the if there is a faster way to solve this problem not back solve. Thanks, ravsav.

Hi, I am facing the same problem. Third degree polynomial it is. And it is lengthy. I did not even complete solving it thinking there must be some easy way to do it. Looks like there is not!! Thanks for your input. ravsav.

Hi Can somebody help me here. The perimeter of an isosceles triangle is 16 units and its area is 12 sq.units. Find its sides. Thanks ravsav

Hi Thanks for all the explanations. Now if one clock gains and other looses 6 hrs, one should be showing 6 AM and the other 6PM after 360 hrs, right? ravsav

Hi Correct me if I am wrong. I had patience to sit and write down the times after every 12 hours of both the clocks (i.e., after 12 hours one shows 11.48 and the other shows 12.12 and so on). I am arriving at 6 PM after 360 hours when both the clocks show the same time. Does that mean after actual 360 hours i.e., 15 days, both the clocks will be showing the same time 6 PM which is wrong time? Thanks, ravsav.

Hi, I have no idea regarding the answer, but can someone tell me how to solve it. Two clocks register twelve 'O' clock midnight at exactly the same time. One clock looses one minute each hour and the other gains 1 minute every hour. Assuming that each will continue to loose or gain at the same rate, when will both register the same time again. Thanks in advance, ravsav.

The first one is 3/8. I don't know the second one's answer. I came across it while doing some extra reading on probability and Pascal's Triangle. Thats when i got this doubt and posted this question.

I want to know whether the following two types of problems have same type of solutions. Tossing a penny 3 times, what is the probability that there will be 2 heads and 1 tail. What is the probability that in a family of three kids, there will be 2 boys and 1 girl. thanks

Hi Riz, looks like i am good at goofing up!!!! Yes you are right, 150% of 25000 cannot be 17,500:hmm: I think I should check twice before i post!!!So the oct sales will be 62,500. thanks

Hi GMAT I also took that approach. Only thing is I did a small mistake while changing the E equation in y=mx+c form. Even E has negative slope. Ravsav

let the sept sales be x Then 20% of x + x = 30,000 Gives you x = 25,000 i.e., Sept Sales Now if Oct was 150% increase in sales compared to Sept., then 150% of 25,000 = 17,500 Then in this scenario Oct sales will be 25,000 + 17,500 = 42,500 correct me if I am wrong.

Looks like everybody figured out the answer excepting me. Now I know where I went wrong.

Hi The answer is B. The equation x = 1 - 1/3 y can be written in the slope intercept form i.e., y = mx + c form where m is slope of the line and c is the y intercept. So x = 1 - 1/3 y can be written as y = -3x + 3 And this equation represent a line with negative 3 slope and and y intercept as 3 which satisfies the given graph. No other equations satisfies this. A, D, E show negative y intercept which is not the case from the graph. C has positive slope so that is also not the answer. So B is your answer. Ravsav.

Now i get it!!!! Thank you. ravsav

Hey Gmat Help, I was trying to understand your first explaination and was successful to a certain extent!! Can you do the last calculation part i.e., p(atleast 1Head/atleast 1 Tail) = p(atleast 1 Head + atleast 1 Tail)/p(atleast 1 Tail) = 6/7 Now with your second explaination, if in the scenario that you take the TTT option first for atleast 1 tail. Then all the remaining options has atleast 1 head. Then the Probability will become 7/7=1. Can you explain why we should not take the TTT option for atleast 1 Tail. Thanks again in advance. ravsav.