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priyasom

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  1. These are questions from section1 taken from "1000PS" document. I couldn't get the OA for the foll. 3 questions. Can someone help? Month Average Price per Dozen April May June $1.26 $1.20 $1.08 19. The table above shows the average (arithmetic mean) price per dozen of the large grade A eggs sold in a certain store during three successive months. If 2/ 3 as many dozen were sold in April as in May, and twice as many were sold in June as in April, what was the average price per dozen of the eggs sold over the three-month period? (A) $1.08 (B) $1.10 © $1.14 (D) $1.16 (E) $1.18 (Ans:d) ……………… 5. At a certain diner, a hamburger and coleslaw cost $3.59, and a hamburger and french fries cost $4.40. If french fries cost twice as much as coleslaw, how much do french fries cost? (A) $0.30 B) $0.45 © $0.60 (D) $0.75 (E) $0.90 (Ans: e) …………………… 2. A parking garage rents parking spaces for $10 per week or $30 per month. How much does a person save in a year by renting by the month rather than by the week? (A) $140 (B) $160 © $220 (D) $240 (E) $260 (Ans: B) Thanks.
  2. I agree with Piju. I saw a similar question in PS1000 doc, Section1/ Q#20. Only difference is that the given prime integer is 3x/y and not 2x/y. Considering the prime number is 3x/y, can someone explain the answer? Well, the OA is None.
  3. I found this problem in PowerPrep. When a certain tree was first planted, it was 4 feet tall, and the height of the tree increased by a constant amount each year for the next 6 years. At the end of the 6th year, the tree was 1/5 taller than it was at end of the 4th year. By how many feet did the tree increase each year? a) 3/10 b) 2/5 c) 1/2 d) 2/3 e) 6/5 Ans: d Can someone explain this one to me? I couldn't get the OA.
  4. S is the total sales. So, for any sales above $1000, the value will be S-1000. For. e.g if A made a sale of $2000 (assume, that is the total sales), then the variable component will become 6% of (2000 -1000).
  5. The assumption made here is that a triangle is made up of only 3 points. Hence considering the 3 colinear points to form one leg of the triangle will increase the total number of points to 4.
  6. For the second question, I think x = (2^i) (3^k) (5^m) (7^p) Each of the prime numbers raised to specific powers. Then if we modify the first statement, x = 1*2*3*....8 break it into products of prime numbers alone then x = (2^7) (3^2) (5^1)(7^1) i+k+m+p = 7+2+1+1 = 11
  7. Hi Nexus_Connection, I didn't do anything different. Followed the good old barrons. My prep was for 2 and 1/2 months. I did the ETS math review. Continued with barrons word list. Looked at questions posted in TM's Math and VErbal forums. Then towards the end started taking tests from Big Book and Barrons. Ofcourse, i took 2 PP tests also in between. Don't worry. Give it a second shot . You have already have the advantage of the first experience with you now. All the best. Priya
  8. Hi people, Problems i got in the series n sequences were formula based. And yes, i did get some std. deviation based problems. But i couldn't understand those. :-( One of the main reasons as to why i m unable to post it here. Sorry guys. For quants, i found the big book questions to be too easy. Barrons would be much better. Also, the barrons model tests at the end are very good indicators of the type of questions which would come in real gre. i took the model tests just 1 day before the exam and found that some of my maths fundas had to be brushed up. So, people do try those model tests for quants. Thanks once again for all the "congrats" that i m getting from you all :-)
  9. Hi people, Barrons is good enough for verbal. I got one or two non-barrons words but you can try and make a fair guess. In Quants, maybe you can look at Series and Sequences, Probability problems apart from the normal chapters in ETS review. All the best for your test on 25th, asmit Priya
  10. Thanks guys. I am mostly looking at Computational Biology related areas. So, i have just started looking at the various univs. Should come up with a list pretty soon. And my test experience was quite normal. Normal in the sense, i was feeling quite tensed. The AWA topics were quite easy . I got a research section where i got an Argument analysis. Ended up writing 3 essays :-) Verbal was just like in BB. But i found quants difficult. In the PP tests, i had averaged around 760 sorts. Somehow in the real test i couldn't pick up many points. Testmagic has been of help in a big way. The math problems i got here were very helpful. Best of luck for your exam. Priya
  11. Made a score of 1330. Verbal 630 Quant 700 Thanks a lot guys. Posts at testmagic have been a big help to me. I found the quants section a bit tough. Infact its much tougher than the powerprep problems. Best of luck to all those who are going to take the test in the future. Priya
  12. Thanks arjmen. I got it . Priya
  13. Hi, i came across this problem recently: If the sum of all the positive even integers less than 1000 is A, what is the sum of all the positive odd integers less than 1000 ? a) A - 998 b) A - 499 c) A + 1 d) A + 500 e) (A/2) + 999 Can we use the concept of Arithmetic progession in this problem ? priya
  14. priyasom

    probability

    Hi Apprentice, We have been given a set of no.s from which we can choose our digits { 0,1,2,3,4,5} so, from this list if we look at the 2 digit no.s more than 50 and having the digits from above set, then in the tens digit only the value 5 will come and in the units digit, you can fit in { 1,3,5} as these only make the no. odd. so, going by these constraints we have : for tens digit : 1 way for units digit : 3 ways totally no. of two digit nos = 1 * 3 - (A) now, lets look at the three digit no.s - hundreds digit can be { 1,2,3,4} - 4 ways tens digit {0,1,2,3,4,5 } - 6 ways units digit - {1,3,5} - 3 ways that way, total three digit no.s = 4 * 6 * 3 - (B) But then we need only those no.s which are less than 450. in the above case we will get no.s which are above 450. So to subtract those hundreds digit - {4} - 1 way tens digit - { 5 } - 1 way units digit - {1,3,5} - 3 ways value to be subtracted - 1 * 1 * 3 = 3 © Finally, A+ B - C = 3 + 72 - 3 = 72 Hope this cleared your doubt. priya
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