solawgmat Posted January 2, 2009 Share Posted January 2, 2009 If y>=0, what is the value of x? (I) abs(x-3) >= y (II) abs(x-3) Quote Link to comment Share on other sites More sharing options...
12rk34 Posted January 2, 2009 Share Posted January 2, 2009 (1) lx-3l >= y => (x-3) >= y and (x-3) >= -y =>(x-y) >= 3 and (x+ y) >=3 Adding, 2x >= 6 => x >= 3 INSUFFICIENT (2) lx-3l Since absolute value can not be -ve, x-3 = 0 => x=3 SUFFICIENT Hence B :) Quote Link to comment Share on other sites More sharing options...
solawgmat Posted January 3, 2009 Author Share Posted January 3, 2009 Very nice. I didnt think about the function of the absolute value other than to write two seperate inequalities. Thanks![clap] Quote Link to comment Share on other sites More sharing options...
genius_in_the_gene Posted January 5, 2009 Share Posted January 5, 2009 IMO B 1) |x-3| >=0 Not suff 2) |x-3| Since y>=0 and abs values cant be x-3=0 x=3 Quote Link to comment Share on other sites More sharing options...
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