Da_Gr8_Mperor Posted April 28, 2006 Share Posted April 28, 2006 If M is a finite set of negative integers, is the total number of integers in M an odd number? (1) The product of all the integers in M is odd (2) The product of all the integers in M is negative (A) Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient. (B) Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient. © BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient. (D) EACH statement ALONE is sufficient. (E) Statements (1) and (2) TOGETHER are NOT sufficient. Quote Link to comment Share on other sites More sharing options...
GMAT-HELP Posted April 28, 2006 Share Posted April 28, 2006 Stmt 1: Insufficient: -1*-3* = 3 (product is odd) but the number of integers is even(2) -1*-3*-5* = -15 (product is odd) but the number of integers is odd(3) so inconclusive.. Stmt 2: Sufficient Product is -ve means number of -ve integers should be odd as product of even number of -ve integers will always be +ve..(above example still holds good) Ans B. Thanks, GMAT-HELP Quote Link to comment Share on other sites More sharing options...
Rachita7 Posted April 28, 2006 Share Posted April 28, 2006 The answer is B) A) If M = {-3, -7} The product is 21 which is odd, when the number of integers is even. - Insufficient B) M will always have odd integers if the product is negative, as even (negative) number of integers will always yield a positive product. - Sufficient Quote Link to comment Share on other sites More sharing options...
manish8109 Posted April 28, 2006 Share Posted April 28, 2006 Agree with rachita & Gmat help, Ans should be B Quote Link to comment Share on other sites More sharing options...
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