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number = 5n

Stmt 1:

4x+3

=> 5n = 4x+3 => (6x-2x+3)/6 => remainder will vary with the value of x

=> x can be 3,8,13,18, 23 and so on

=> number = 15, 35, 55...

=> remainder can be 3, 5, 1...

Insufficient

 

Stmt 2:

12x+3

=> 5n = 12x+3

=> (12x+3)/6 always leaves a remainder 3..(number = 15,75,135 and so on)

Sufficient

Ans B.

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