ndcruz Posted April 1, 2008 Share Posted April 1, 2008 If x is equal to the sum of the even integers from 40 to 60, inclusive, and y is the number of even integers from 40 to 60, inclusinve, what is the value of x+y? (A) 550 (B) 551 © 560 (D) 561 (E) 572 OA: D Quote Link to comment Share on other sites More sharing options...
krovvidy Posted April 2, 2008 Share Posted April 2, 2008 There would be 11 even integers from 40 to 60 .... As these are consecutive, we can say that SUM of those is (40+60/2) *11 = 550. So, the final answer is 550+11 = 561 (D) Quote Link to comment Share on other sites More sharing options...
Dynamo Posted April 2, 2008 Share Posted April 2, 2008 D 561 Quote Link to comment Share on other sites More sharing options...
ve_boss Posted April 2, 2008 Share Posted April 2, 2008 Sorry about this question, but I like to be convince by formula. (my french side I guess..) : can someone explain this step : As these are consecutive, we can say that SUM of those is (40+60/2) *11 = 550 It reminds me smth but I don't manage to demonstrate this formula again. Thanks ! Quote Link to comment Share on other sites More sharing options...
ve_boss Posted April 2, 2008 Share Posted April 2, 2008 ok. I just remembered that sum(1,n) = n*(n+1)/2, which is a particular arithmetic serie. But I forgot that http://upload.wikimedia.org/math/9/a/5/9a5fb55b3d24acaa271a9e4eea85cd83.png :blush: Quote Link to comment Share on other sites More sharing options...
Dynamo Posted April 2, 2008 Share Posted April 2, 2008 Sn= {n+1(first term + Last term)}/2 AP ..... Quote Link to comment Share on other sites More sharing options...
Dynamo Posted April 2, 2008 Share Posted April 2, 2008 ok. I just remembered that sum(1,n) = n*(n+1)/2, which is a particular arithmetic serie. But I forgot that http://upload.wikimedia.org/math/9/a/5/9a5fb55b3d24acaa271a9e4eea85cd83.png :blush: n(n+1)/2 is only for a series of HP 1+2+3+4+5...... +n.... Quote Link to comment Share on other sites More sharing options...
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