sserendipty Posted November 30, 2015 Share Posted November 30, 2015 In performing a sequence of experiments, a scientist made 20 measurements. The average (arithmetic mean) of these measurements was 34. For security reasons the scientist coded the data by multiplying each of the measurements by 10 and then adding 40 to each product. What is the average of the coded measurements? (A) 1,140 (B) 380 © 342 (D) 57 (E) 19 Answer: B Quote Link to comment Share on other sites More sharing options...
Brent Hanneson Posted November 19, 2016 Share Posted November 19, 2016 In performing a sequence of experiments, a scientist made 20 measurements. The average (arithmetic mean) of these measurements was 34. For security reasons the scientist coded the data by multiplying each of the measurements by 10 and then adding 40 to each product. What is the average of the coded measurements? (A) 1,140 (B) 380 © 342 (D) 57 (E) 19 Answer: B A quick solution is to say that the original 20 measurements were all 34 That is {34, 34, 34, 34, 34, 34, 34, 34, 34, 34, 34, 34, 34, 34, 34, 34, 34, 34, 34, 34} These values definitely have an average of 34 For security reasons the scientist coded the data by multiplying each of the measurements by 10 and then adding 40 to each product. 34 times 10 equals 340. Add 40 to get 380 So, the 20 coded values are {380, 380, 380, 380, 380, 380, 380, 380, 380, 380, 380, 380, 380, 380, 380, 380, 380, 380, 380, 380} New average = 380 Answer: B Cheers, Brent Quote Link to comment Share on other sites More sharing options...
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