mrajatish

2 - (-1) = 3, which means & = - and k = -1, hence, 3&K will be 4, so yes you are right.

it should be x + 2y = 27, since each teacher will teach either one or more class (they already teach one class). Hence, max (y) = 13 and min (y) = 0.

A wire 40 m long is cut into 2 pieces, one is used to form a circle with radius r and the other is used to form a square. No wire is left over. What is the total area of the circular and the square regions in terms of r? Pie r2 Pie r2+10 Pie r2+1/4 pie2 r2 Pie r2+(40-2pie r)2 Pie r2+(10-1/2pie r)2 Total perimeter of square + circle is 40. Perimeter of circle is 2pier. Hence, perimeter of square = 40-2pier. Hence, each side is 10-pier/2. Now, you can get sum of areas. If x What are the choices? since x 0, and mod(x) > 0 so end result of product is x^2, then whole root becomes -x or mod(x).

Check if x and y are both -ve - your eq will not hold then. In general, you cannot multiply inequality unless you know the sign.

Can you explain why 0 is divisible by 2? I have a bit of confusion here. Is it because remainder has to be 0 when a is divided by b for us to say: a is divisible by b?

Can you have equal sides with being parallel in a quadrilateral? I am having a hard time visualizing a quadrilateral with opp.sides equal but opp. angles unequal. I think if you draw the bisector of the quadrilateral, it can be easily shown by SSS that the two triangles are congruent, and once they are, opp. angles are equal, hence parallelogram. Hence, ans. is C.

Is it A?

native language of the students: 20 Spanish, 15 French, 15 Chinese. And then Exactly 30% of the students speak French Just because my native language is Hindi does not mean I only speak Hindi. So, I may speak FRench too and I should be added too. Hence, A is out. People whose native tongue is French can speak English too. And no one can speak more than 2 languages. Hence, there are only 15 people who speak french and they comprise 30% of all students. Hence, Ans is C.

x = 2, y = 2 => 2x is not a multiple of y I am confused here, is 4 not a multiple of 2?

Absolutely agree From Part 1, the slope is -1 which makes it impossible to have the original straight line From part 2, we can have two eqns, one of which satisfies the problem, hence cannot accept it. The problem states Is w the eqn of a st. line, which may or may not be the case in 2. Ans has to be A.

Doesn't x=2, y=-3 and x=-2,y=3 both satisfy xy^2 = 18 and xy =-6. So we have two solns, so B cannot be true. Also A cannot be true. (x+y) can be + 1 or -1. Combining, we are still in no position to make sure what x +y will be. So answer is most likely E.

let the series start from x and the space between the numbers be w. So, numbers are x, x+w, x+2w, x+3w and x+4w Eqn 1 x+2w = 0; Insuff Eqn 2 4w = 4 Insuff Combine and you get x = -2, w = 1 Ans ©

For question 2, 10/2 > 10/3 > 10/5 > 0 ( A > B > C > 0) now, invert 2/10 + 3/10 + 5/10 = 1 So, C can be > 1/2. Infact, to satisfy the problem, c > 1. So, A is true. B has been rightly discarded.

Yes, (x*600 + (25-x)*300)/25 = 540 Solve for x and you can then calculate (x*600 +(30-x)*300)/30

I am finding that number line approach is simple and intuitive in these cases, and if you are ever in doubt, as you might well be in the actual test, just plug in some value to prove that inequlity is wrong from the number line. Is that a good approach - looking for help on a general strategy to nail these down.