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If a question is like below: Col A: 4*sqrt(4) Col B: sqrt(36) What should be the answer? Should we take only the positive square root or the negative square roots as well. In case we take the negative roots also, answer will be D. In GRE, Can we assume that sqrt(4) always means the positive square root? I'm not sure about it. Please carify ...

Sorry ... this post has made twice because of connectivity problem (pressing the submit button twice) ... I couldn't delete the post ...

Can anybody please solve the following problems for me? I don't have OA. A) Given a triangle with sides AB=5 & BC=13. If AB:BC = 5:13, then what is ratio of BC:AC? B) Given that 500 people were asked two questions whether to say either 'yes' or 'no'. Of that, if 410 people said yes to first one and 220 people said yes to second question. What is the least number that said yes to both? A. 90 B.110 C.150 D.190 E. 220

Can anybody please solve the following problems for me? I don't have OA. A) Given a triangle with sides AB=5 & BC=13. If AB:BC = 5:13, then what is ratio of BC:AC? B) Given that 500 people were asked two questions whether to say either 'yes' or 'no'. Of that, if 410 people said yes to first one and 220 people said yes to second question. What is the least number that said yes to both? A. 90 B.110 C.150 D.190 E. 220

Unit digits of perfect squares are never 2,3,7, or 8 (x+y)^2=9 ==> x + y = 3 or -3 subtracting it frm the 1st equation ==> y = 5 A number is divisible by 3 if summation of its digits are divisible by 3 1 + 5 = 6 7 + 5 = 12 1 + 2 + 3 = 6 2 + 9 + 7 = 18 3 + 1 + 3 = 7 not divisible by 3. Therefore, this is the answer 20^8 = 20 * 20^7 20/4 = 5 so,(1/4)(20^8) = 5(20^7) (3+1/7) - 7/22 7/22 is almost 1/3 Since, 1/3 - 1/7 = 4/21 So, The value will be greater than 2.5 => nearest integer 3

Yes you are right. So, the answer should be 6*3!*2 = 72 Thank you very much

Can anybody please solve the following problems??? 1. If 40% of y is multiplied to 50% of 3y, then how much percent is it to 2y^2s? 2. Given that 7 workers working together finish a work in 140 hrs. If starting 4 workers takes 'h' hrs each and rest 3 takes '2h' hrs each to complete the work then what is the difference between the median and mean of the individual working hours?

I am not considering 4 "Chairs" ... rather considering 4 "gaps" ... From the 4 gaps only 3 will be used ... so a total of 6 chairs will be used at a time ...

Let us denote girls as G1, G2, and G3 And boys as B1, B2, and B3 Let us first make the girls sit together (ladies first indeed). G1,G2,G3 G2,G1,G3 .............. .............. (total 3! = 6 permutations) Now, let us make gaps in both sides of the girls ... _G1_G2_G3_ So, a total of 4 gaps are there where boys are to be inserted. B1 G1 B2 G2 B3 G3 B2 G1 B1 G2 B3 G3 ............................. ............................. (Total 4P3 = 24 permutations for this setting of girls) Therefore, total 24*6 = 144 different arrangements are possible ... Let me know if I am wrong:hmm:

"decibel" is this type of scale. 40 = 10logx => x = 10^(40/10) = 10000

Yes ... now I understood ... Thanks friends ...

Can anybody please describe a fast method for solving the following type of problem? AD>0 Col A: A-B Col B: C-D I don't have any OA.

I think this problem is similar to the following one (I have forgotten where did I get it). A family has two children. We know one of them is a boy. What is the probability of the other one being a boy? ANS: In general, 4 possibilities are there. [b b], [b g], [g b], and [g g] However, the last one is not possible if we know that one child is boy. [b b], [b g], [g b] So, the probability of other child being boy = 2/3 Please make me correct if I am wrong

You cannot eliminate w like that ... what if w=0??? Column A = Column B = 0 Right? So, ans D

This question would be ambiguous if it would state to assume any three points on a circle. However, in this case, it is clearly depicted that only line AB runs through the center. IMO, that is why, the answer A is more convincing as an OA.