actuary0123

NOVA provides a lot of exercises to cement different concepts but it does not do a good job in teaching these concepts...so find a book to teach yourself and then hit NOVA math course. Good luck

Here is another look at this problem: 1st term: 1 2nd term: 1+4 3rd term: 1+4+4 4th term: 1+4+4+4 so there is a constant of "1" in each term and number of "4's" being one less than the number of the term implying that the nth term will have a constant of 1 and (n-1) "4's" which can be mathematically expressed as 1 + (n-1)4 that simplifies to "4n-3".

What is the probability of two randomly chosen numbers (even numbers between 1 and 9) adding to 8? The answer is 1/6. I have read some other explanations but I am a little confused with the details. The question does not imply that this in an experiment without repetition. So essentially, you can pick 4 and 4 and they will add to 8. Also, wouldn't the set {2,6} be different from {6,2} in this particular case? Thank you for your comments.

are your "clicked" answers right or wrong?

All the answers break down in to multiples of 2 and 3 except 42 which has a 7 in it.

Well, fatuity stupidness or unwise => antonym will mean something "wise" and that is choice B. But then again, I already know the answer :)

The catch, which I missed as well, is that they are asking about the number of men and women on the panel AFTER replacing one woman by a man. Before replacement, you have 4M = 3W => M=W x 3/4 (this equation will guide the number of women to be positive multiples of 4 because "partial" or "negative" women do not exist "yet"). After replacement, the revised number of males and females will be M+1 and W-1 respectively. W=4 => M=3 => M+1 = 4 & W-1 = 3 => A W=8 => M=6 => M+1 = 7 & W-1 = 7 => C Since two quanitities cannot be equal and unequal at the same time, you click D at this point.

Set of numbers: {-14, -7, -2, 12, 16, 20) i)std dev > mean ii)std dev iii)mean = median The answer choices had some mix and mathc of these options but I am really concerned about making a reasonable estimate of std. dev. without going through the details of actual calculations. Any comments?

I looked at this problem last night and it has me stumped. I was following the same logic as "goguma" above but the area of the triangle STU with an intermediate step Are of a Triangle = .5 x base x height Area (STU) = A (STU) + A(UVT) = .5 x VT x VS + .5 x VU x VT = .5 (VT x SU) Area RTSU = 2 x A(STU) = 2 x .5 x (VT x SU) = VT x SU => C I thought the intermediate step was necessary. I just thought to add the explanation of this problem in logical steps without omitting any intermediate steps.

wow...I didn't even think of that...so easy! Thanks.

What is the greatest prime divisor of (64^2 - 57^2) ?? Supposedly, the answer is 11 but I want to know a quick way to find the answer. Thank you for your comments/help.

WORK = RATE X TIME 140 =4 X (1/h) + 3X (1/H) => H = 770 Mean = (4xh + 3x2h)/7 = 10h/7 = 1,100 Median = h = 770 Difference = 1,100 - 770 = 330