Red Bozo

Hi, I just needed 1 clarification...as far as GMAT is concerned, is sqrt(100) = 10??? Or is sqrt(100) = +/- 10???

[TABLE=class: grid, width: 100, align: center] [TR] [TD]Clicks [/TD] [TD]Berks [/TD] [TD]Ticks [/TD] [TD]Albs [/TD] [/TR] [TR] [TD]1 [/TD] [TD]4-7 [/TD] [TD]77 [/TD] [TD]231-233 [/TD] [/TR] [TR] [TD]7 [/TD] [TD]28-31 [/TD] [TD]11 [/TD] [TD]33-35 [/TD] [/TR] [TR] [TD]11 [/TD] [TD]44-47 [/TD] [TD]7 [/TD] [TD]21-23 [/TD] [/TR] [TR] [TD]77 [/TD] [TD]308-311 [/TD] [TD]1 [/TD] [TD]3-5 [/TD] [/TR] [/TABLE] I think the answer is A. Here's the explanation: Since the score is 77, we can have the clicks and ticks taking values as shown above. Also, it isn't stated that the Berk count is a multiple of 4. Likewise, the Alb count needn't bee a multiple of 3. So, if click count = x, then berk count can be 4x, 4x+1, 4x+2 or 4x+3. Likewise, if tick count = y, then alb count can be 3y, 3y+1 or 3y+2. That's the basis for the data in the above table. Now consider statement 1: Alb - Berk = 7. So obviously it can't be row1 or row 4, because of the huge differences. Row 3 also has widely-spaced Alb and Berk values. Since Albs Now consider statement 2: No of Albs captured is divisible by 4. Thr's no such value in row2 and row 3. Row 1 and Row 2 both satisfy the condition. But we still can't zero in on one of these rows. So statement 2 alone is not sufficient. So answer is A.

For Q1, this is what I did...seemed easier than taking values: Since u and v are +ve real nos., we have: A. v>u3 B. v>u1/3 Case 1: u Case 2: u>1... so on the number line: 0___u1/3___u___u3 Case 3: u=1. Now, in case 1: v can be either side of u and still satisfy statement A, so obviously A alone isn't sufficient. Likewise, in case 2: v can be either side of u and still satisfy statement B, so obviously B alone isn't sufficient. Considering both statements together, we see that v has to be greater than both u1/3 and u3, but in both case 1 and 2, u is between u1/3 and u3, so v is BOUND TO BE greater than u. So both together are sufficient. Case 3 need not be considered since A and B individually get eliminated by Case 1 and 2.