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jangok

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  1. Here we have the following thing.. as much as 20% of the leaf and small-stem material.. Keep the following in mind much is always used for non-countable nouns(ie. singular nouns) many for plural/countable ones So we need a singular verb here..which is supplied by D. shatters and falls Hence the answer you may check this as well http://www.TestMagic.com/forum/topic.asp?TOPIC_ID=4158
  2. E is right. In life-styles requiring require vast wild spaces and permitting little accumulation of goods ... the part "requiring...." correctly modifies life-styles. seems inevitably doomed correctly refers to the subject "the disappearance of.." In Choice A - seems has sub-verb agreement problems C - uses "which" wrongly
  3. Q1 The question says that nne of the five answer choice is a multiple of 24. Reason: No of hours in a day = 24 So lets take the prime factors of 24 are 2,2,2,3 (ie 24 = 2*2*2*3).. OR any combination there of. ie. 2,3,4,6,8,12,24 A look into the choices given shows that last 2 digits are given in all choices.. I would straight away check for 4 because ..by doing this we can eliminate many choices Any number whose last two digits is a multiple of 4 is a multiple of 4 as a whole. For eg. 112 is a multiple of 4 as 12 is a multiple of 4. Similarly 271 is NOT a multiple of 4 as 71 is not a multiple of 4....Hope you got it.. Keep this basic rule in mind. By applying this technique we can eliminate all answer choices except E, and Hence the answer is E
  4. The phrase 'begun almost two decades ago' correctly modifies "An attempt to ratify the Equal Rights Amendment"
  5. 3. A study of children of divorced parents found that ten years after the parents' divorce, children who had been six years of age at the time of the settlement were not preoccupied, nor even very curious, about the reasons that led to their parent's divorces. A. B. not preoccupied with, or even very curious about, the reaons for their parents' divorce D. neither preoccupied with the reasons that led to thier parents divorce or even curious about them D is right, i opted B. Why is B wrong? Is D really right?? neither preoccupied with the reasons that led to thier parents divorce nor even curious about them. My question is curious about what?? What is the antecedent of pronoun "them".? The original sentence suggests that it should be "reasons", but is it possible for "them" to point to the part inside neither?
  6. Choice A is the only correct one. C,D,E are all out because of modifiers problem. B is wrong because the "which" modifies the transfusions, instead of the "whole blood" as in the case of choice A.
  7. B is correct.. here it correctly compares 'people' vs 'people', while in (A) it is between people & person, not the same thing at all.
  8. I go with B in Q1. I dont know how to explain it properly.. 1. It is the government regulations that is establishing standards..So need something to connect both. For me for this one reason alone, the present participle(or is it??) "establishing" in choice B stands out as a big contendor. 2. The parallelism issues are minor concerns here.Two things that need to be parallel is guarantee wider access to people.... and to workers.... So I guess the "to...to..." format is superior to the "for...for..."
  9. The new regulations mandate that a company allows their retiring employees who would otherwise lose group health care coverage to continue the same insurance at their own expense for a specific period. (A) that a company allows their retiring employees who would otherwise lose group health care coverage to continue (B) companies to allow their retiring employees who would otherwise lose group health care coverage that they can continue © that a company allow its retiring employees who would otherwise lose group health care coverage to continue (D) companies allowing a retiring employee whose group health care coverage would otherwise be lost the continuation of (E) companies to allow a retiring employee whose group health care coverage would otherwise be lost the continuation of Answer to follow soon..
  10. Or the straight forward way... X = half of passengers Total average = (180x+215x)/2x => 195. So 2000/195 gives 10 ..(fter ignoring the fractional part as we are dealing with number of peoples here..)
  11. I guess you have to do it the whole way... But you can do small short cuts.. like eliminate 1/3 & 2/3 as they have only one digit..(0.33333 & 0.66666) Can there can never be two answers right. 2/11 = 0.1818.. 41/99 = 0.4141.. No need to do any more further and you can select E as A & C have two digits each and both cant be right at the same time.. I beleive this method is atleast a little bit better than doing all 5 choices.
  12. Q1. E Reason: No of hours in a day = 24 Factors of 24 are 2,2,2,3.. and any combination there of. ie. 2,3,4,6,8,12,24 A look into the numbers show that last 2 digits are given in all.. I would straight away check for 4 because of this..as we can eliminate many choices Any number whose last two digits are a multiple of 4 is a multiple of 4 as a whole. For eg. 112 is a multiple of 4 because 12 is a multiple of 4. Keep this basic rule in mind. By applying this technique we can eliminate all answer choices except E, and Hence the answer is E
  13. Let x be the time required in hours to reach Jeff's home.....Since the distance travelled on both trips are same.. we can get the following equation from the question, using the Formula Distance = Speed*Time 40(x+12/60) = 48(x+7/60) => 40x+40*12/60 = 48x +48*7/60 => x = (40*12/60-48*7/60)/8 => 3/10 hrs Substrituting this value into the first equation 40(y+12/60).. we can get the distance 40(3/10+12/60) = 40*(30/60) = 40*1/2 => 20miles Answer: 20miles
  14. I put this topic in the forum..Maybe its helpful http://www.TestMagic.com/forum/topic.asp?TOPIC_ID=1699
  15. Arranging Objects The number of ways of arranging n unlike objects in a line is n! (pronounced ‘n factorial’). n! = n × (n – 1) × (n – 2) ×…× 3 × 2 × 1 Example How many different ways can the letters P, Q, R, S be arranged? The answer is 4! = 24. This is because there are four spaces to be filled: _, _, _, _ The first space can be filled by any one of the four letters. The second space can be filled by any of the remaining 3 letters. The third space can be filled by any of the 2 remaining letters and the final space must be filled by the one remaining letter. The total number of possible arrangements is therefore 4 × 3 × 2 × 1 = 4! The number of ways of arranging n objects, of which p of one type are alike, q of a second type are alike, r of a third type are alike, etc is: n!/(p! q! r!) … Example In how many ways can the letters in the word: STATISTICS be arranged? There are 3 S’s, 2 I’s and 3 T’s in this word, therefore, the number of ways of arranging the letters are: 10! = 50 400 3! 2! 3! Rings and Roundabouts The number of ways of arranging n unlike objects in a ring when clockwise and anticlockwise arrangements are different is (n – 1)! When clockwise and anti-clockwise arrangements are the same, the number of ways is ½ (n – 1)! Example Ten people go to a party. How many different ways can they be seated? Anti-clockwise and clockwise arrangements are the same. Therefore, the total number of ways is ½ (10-1)! = 181 440 Combinations The number of ways of selecting r objects from n unlike objects is: nCr = n!/r! (n – r)! Example There are 10 balls in a bag numbered from 1 to 10. Three balls are selected at random. How many different ways are there of selecting the three balls? 10C3 = 10! = 10 × 9 × 8 = 120 3! (10 – 3)! 3 × 2 × 1 Permutations A permutation is an ordered arrangement. The number of ordered arrangements of r objects taken from n unlike objects is: nPr = n!/(n – r)! Example In the Match of the Day’s goal of the month competition, you had to pick the top 3 goals out of 10. Since the order is important, it is the permutation formula which we use. 10P3 = 10!/7! = 720 There are therefore 720 different ways of picking the top three goals. Probability The above facts can be used to help solve problems in probability. Example In the National Lottery, 6 numbers are chosen from 49. You win if the 6 balls you pick match the six balls selected by the machine. What is the probability of winning the National Lottery? The number of ways of choosing 6 numbers from 49 is 49C6 = 13 983 816 . Therefore the probability of winning the lottery is 1/13983816 = 0.000 000 071 5 (3sf), which is about a 1 in 14 million chance The probability of an event occurring is the chance or likelihood of it occurring. The probability of an event A, written P(A), can be between zero and one, with P(A) = 1 indicating that the event will certainly happen and with P(A) = 0 indicating that event A will certainly not happen. Probability = the number of successful outcomes of an experiment the number of possible outcomes So, for example, if a coin were tossed, the probability of obtaining a head = ½, since there are 2 possible outcomes (heads or tails) and 1 of these is the ‘successful’ outcome. Using Set Notation Probability can be studied in conjunction with set theory, with Venn Diagrams being particularly useful in analysis. The probability of a certain event occurring, for example, can be represented by P(A). The probability of a different event occurring can be written P(B). Clearly, therefore, for two events A and B, P(A) + P(B) - P(AnB) = P(AuB) P(AnB) represents the probability of A AND B occurring. P(AuB) represents the probability of A OR B occurring. Mutual Exclusive Events Events A and B are mutually exclusive if they have no events in common. In other words, if A occurs B cannot occur and vice-versa. On a Venn Diagram, this would mean that the circles representing events A and B would not overlap. If, for example, we are asked to pick a card from a pack of 52, the probability that the card is red is ½ . The probability that the card is a club is ¼. However, if the card is red it can't be a club. These events are therefore mutually exclusive. If two events are mutually exclusive, P(AnB) = 0, so P(A) + P(B) = P(AuB) Independent Events Two events are independent if the first one does not influence the second. For example, if a bag contains 2 blue balls and 2 red balls and two balls are selected randomly, the events are: a) independent if the first ball is replaced after being selected b) not independent if the first ball is removed without being replaced. In this instance, there are only three balls remaining in the bag so the probabilities of selecting the various colours have changed. Two events are independent if (and only if): P(AnB) = P(A)P(B) This is known as the multiplication law. Conditional Probability Conditional probability is the probability of an event occurring, given that another event has occurred. For example, the probability of John doing mathematics at A-Level, given that he is doing physics may be quite high. P(A|B) means the probability of A occurring, given that B has occurred. For two events A and B, P(AnB) = P(A|B)P(B) and similarly P(AnB) = P(B|A)P(A). If two events are mutually exclusive, then P(A|B) = 0 . Example A six-sided die is thrown. What is the probability that the number thrown is prime, given that it is odd. The probability of obtaining an odd number is 3/6 = ½. Of these odd numbers, 2 of them are prime (3 and 5). P(prime | odd) = P(prime and odd) = 2/6 = 2/3 P(odd) 3/6 :)
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