gmat009 Posted November 12, 2008 Share Posted November 12, 2008 In the xy-coordinate plane, line L and line K intersect at the point (4,3). Is the productof their slopes negative? 1) The product of the x-intercepts of lines L and K is positive 2) The product of the y-intercepts of lines L and K is negative Can someone plz. explain this Quote Link to comment Share on other sites More sharing options...
supersuj Posted November 12, 2008 Share Posted November 12, 2008 good question IMO, C Important to note that (4,3) does not matter, what matters is that they intersect in first quadrant Statement 1--> Product of x-intercepts is +ve, which means x intercepts are both +ve or both -ve product of slopes could then be +ve or -ve..........INSUFFICIENT Statement 2--> y intercepts have opposite signs again product of slopes can be +ve or -ve..........INSUFFICIENT Combining(1) and (2), both x-intercepts must be +ve(CANNOT be -ve since they wont interesect in quad 1) and one line has +ve y-intercept , the other a -ve y-intercept, thus product of slopes is negative.......SUFFICIENT Quote Link to comment Share on other sites More sharing options...
genius_in_the_gene Posted November 13, 2008 Share Posted November 13, 2008 Let the equations of the lines be y=mx+c y=nx+d 1)x intercepts will be -c/m and -d/n Now -c/m * -d/n >0 -(c/m)*-(d/n)>0 (c/m)*(d/n)>0 cd/mn >0 if cd>0 mn>0 and vice versa Not sufficient 2) y intercepts are c and d cd Not suff From 1 and 2, mn ANS C Quote Link to comment Share on other sites More sharing options...
spring2009 Posted November 13, 2008 Share Posted November 13, 2008 C for me too Quote Link to comment Share on other sites More sharing options...
e.cartman Posted November 13, 2008 Share Posted November 13, 2008 yes, good ds question as explained by supersuj. Combining both equations to get x-intercepts +ve is the part I liked. Thanks! Quote Link to comment Share on other sites More sharing options...
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