Ratio of the sides of R =2:3=2x and 3x [suppose]
Perimeter of R=Perimeter of S=10x
Area of R=6x^2
Area of S=(10x/4)^2=(100x^2)/16
Area of R/Area of S=(6x^2)*16/100x^2=24:25
Plz check ur answer again.
The perimeters of square region S and rectangular region R are equal. If the sides of R are in the ratio 2:3, what is the ratio of the area of region R to area of region S ?
Answer 24 : 25
please explain??
Last edited by kamranalam81; 01-03-2006 at 05:59 AM.
let "a" be the side of the square S,"w" and "l" be the sides of the recatangle R. According to the questions,
Perimeter of square = perimeter of rectangle.
4a = 2w + 2l
Now, w/l = 2/3
therefore,
4a = 2w+2*(3w/2)
4a = 5w and l = 6/5a
Area of rectangle. = w*l = 4/5a * 6/5a =24/25*a^2
Area of squage = a ^2
Take the ratio; you will get 24/25
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