kamranalam81 Posted January 3, 2006 Share Posted January 3, 2006 The perimeters of square region S and rectangular region R are equal. If the sides of R are in the ratio 2:3, what is the ratio of the area of region R to area of region S ? Answer 24 : 25 please explain?? Quote Link to comment Share on other sites More sharing options...
CTG1983 Posted January 3, 2006 Share Posted January 3, 2006 Ratio of the sides of R =2:3=2x and 3x [suppose] Perimeter of R=Perimeter of S=10x Area of R=6x^2 Area of S=(10x/4)^2=(100x^2)/16 Area of R/Area of S=(6x^2)*16/100x^2=24:25 Plz check ur answer again. Quote Link to comment Share on other sites More sharing options...
kamranalam81 Posted January 3, 2006 Author Share Posted January 3, 2006 Thanx... your answer is correct Quote Link to comment Share on other sites More sharing options...
asur Posted March 16, 2006 Share Posted March 16, 2006 Can any one please provide elaborate explanation on CTG1983's explanation for this question... please... I did not understand even a bit.... Thank You.... Quote Link to comment Share on other sites More sharing options...
SmallFish Posted March 16, 2006 Share Posted March 16, 2006 Can any one please provide elaborate explanation on CTG1983's explanation for this question... please... I did not understand even a bit.... Thank You.... Perimeter of square = Perimeter of rectangle 4a = 2l+2w Since the sides of rectangle are 2:3, lets plug the values to the above equation 4a = 2*2+2*3 a= 5/2 So the side of the square is 5/2 Area of rectangle/Area of square = (2*3)/(5/2)^2 = 24/25 Quote Link to comment Share on other sites More sharing options...
yoda_ngen Posted March 16, 2006 Share Posted March 16, 2006 let "a" be the side of the square S,"w" and "l" be the sides of the recatangle R. According to the questions, Perimeter of square = perimeter of rectangle. 4a = 2w + 2l Now, w/l = 2/3 therefore, 4a = 2w+2*(3w/2) 4a = 5w and l = 6/5a Area of rectangle. = w*l = 4/5a * 6/5a =24/25*a^2 Area of squage = a ^2 Take the ratio; you will get 24/25 Quote Link to comment Share on other sites More sharing options...
asur Posted March 16, 2006 Share Posted March 16, 2006 Thank you for posting it... I got it now! Quote Link to comment Share on other sites More sharing options...
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