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rookie2005

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  1. The OA says E (no explns) but not completely convinced my understanding was Stmt1 and Stmt2 are clearly insufficient Basically using stmt 1 and stmt 2 one can figure out that the line cuts through III, II and the I quadrants if extended sufficiently. The probability of a point on the line with both x and y coordinates being negative happens only in the III quadrant hence probability = 1/3 so C :rolleyes: Could someone help please
  2. if point (p,q) is on a certain line segment, what is the probability that both p and q are negative ? 1) point b (-5,-8) is on the line 2) point c (-3,0) is on the line
  3. Prime factorize the denominator and see if there are numbers other than 2 and 5 as prime factors , if there are eliminate those fractions. 196 has 7 and 144 has 3
  4. The total number of ways of putting 4 letters into 4 envelopes can be 1) Case where an envelope can take any number of letters, ie some may be empty and others might have more than 1 = 4*4*4*4 = 4^4 2) Case where every envelope must have atleast one letter = 4*3*2*1 = 24 Why is everyone adding 4 + 4 +4 +4 , Please explain
  5. None match the answer Should be 23 Total ways of putting 4 letters in 4 envelopes (assuming an envelope can only hold one letter) = 4 * 3 * 2 *1 = 24 Total ways of putting all letters in their correct envelopes = 1 Total ways of NOT putting them correctly = 24 -1 = 23
  6. The language was a bit confusing: if Six different balls => Balls A, B, C, D, E, F answer: 3 * 2 * 1 * 3 * 3* 3 = 162 If not then (balls are identical) only three possible sets of numbers satisfy the condition 1 + 2 + 3 ( # of ways = 3! = 6) 1 + 1 + 4 ( # of ways = 3!/2 = 3) 2 + 2 + 2 ( # of ways = 1) Total # of ways = 6 + 3 + 1 = 10 ways
  7. If OA says A , then I guess its wrong :) It should be C , an assumption must support the conclusion. A is a good choice if one is attempting to weaken this argument. The argument is attempting to build a causal relationship between taking courses and reduction in crime Choice A attempts to break this causal relationship : Whether one takes the course or not , the person is likely to commit a crime if he was intending to so Choice C on the other hand clearly establishes this causal relationship by eliminating a weakness in the argument.
  8. CTG , if you search the forum everyone is using a different formula. Just confirm it using Venn Diagram.
  9. Agree with 10 AUBUC=A+B+C-(AnB+BnC+AnC) - 2(AnBnC) + neither 100 = 50 + 30 + 20 - (% who like 2 products) - 2(5) + 15 => (% who like 2 products) = 5% participants who liked more than one of the three products = # who liked 2 products + # who liked all three products = 5 + 5 = 10%
  10. opt C Banning red cars from the roads will not solve any problem since, the accidents occur because of reckless drivers not because of the color of the car . In other words , removing red cars does not affect the # of reckless drivers and hence the accident rates.
  11. prefer E problem with B is the usage of 'which' (non-essential modifier) , should use 'that' (an essential modifier) to modify 'Hunnish troops'.
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