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Question 1: The problem can be expressed in an equation as following: 0.15 X + 0.29 Y = Z, where X and Y are the prices of the stamps, and Z the total amount of the purchase. (1) says that Z = $4.40 It doesn't allow to solve the equation by itself --> INSUFF (2) says that X=Y so we can replace Y by X. We still have two unknown variables (X and Z) --> INSUFF (1) and (2) : replacing all variables by the given information, only X remains --> SUFFICIENT

Hi Surya and good luck in your application I'm french, from Paris, and met several times students from HEC MBA as well as admission officers. My feeling is that not speaking french should not be a weakness of your application (as soon as you have others strenghts such as other foreign languages). For the MBA program, English is required, not French. It is not the case for other HEC programs. On the opposite, staying in France is an opportunity to learn the language and the culture, something you could stress in your application as a proof of your open-mindess and willingness to discover the local and european culture blablabla...(if you're not european) Recent example: I met yesterday a japanese student who came from Columbia at HEC for an exchange during his third semester. He doesn't know french and slowly learns it, but it is not a problem for him to handle the courses and live there. Ok, he didn't exactly apply at HEC MBA, but not speaking french wasn't a problem for his exchange. Eventually, learning a bit of "elementary" french shouldn't be so hard anyway. Hope it encourages you. Good luck again.

Question 2: I would say E: 1:2 There are 10x10x10=1000 small cubes The partly painted cubes are all the outside ones.If we then consider the NOT painted ones, there will be 8x8x8 =512 cubes. So there are 1000-512=488 painted cubes and the probability is 488/1000 which is more or less 1/2.

You're welcome. My pleasure if I can be helpful.

Doing all calculations takes time, and time is a scarce resource at the GMAT. Long explanation, but fast method. It took me 25-30 seconds. Here, understanding the stem precisely is the longest thing to do. The stem asks us to identify the number which has the smallest prime factors, repeated as many times as possible, because with large and numerous distinct prime factors, their product will be a large number, likely to be superior to the square root of the number we're considering. For example, 99 is obviously not qualified, with 11 as a prime factor. There must be a better one. In a glance at the proposed answers, 96 looks good. It appears that 96 = 2x2x2x2x2x3, so there are only two prime factors 2 and 3, and they are the lowest possible positive prime factors. The only numbers that could be better would be ones that could be expressed as 2^n or 3^n or 5^n, since 2, 3 and 5 are inferior to 2x3, the product of the prime factors of 96. But there is no number as such in the propositions. Therefore, 96 HAS to be the solution. Just to make sure, 2x3 = 6 and SQR(96)>SQR(81)=9 --> OK There is no need to check the other answers, therefore saving time.

Zero is an even number. Definition: Integers that are divisible by 2 are even numbers. 0/2 = 0 is an integer, so zero is even (confirmed in OG11 - the GMAT-taker official bible - as said by Herbert) On the opposite, zero is neither positive, nor negative.

1. Prob (BOTH flowers are NOT tulips) = 1 - Prob (Both Flowers ARE tulips) Prob (Both flowers are tulips) = Prob (first flower is tulip) x Prob (second flower is tulip) Prob (first flower is tulip) = 2 tulips / 8 flowers = 1/4 Prob (second flower is tulip) = 1 tulip left / 7 flowers remaining = 1/7 Therefore: Prob (BOTH flowers are not tulips) = 1 - (1/4 x 1/7) = 27/28 What is OA?

Let's call B the brown hair and M the males. Not-B are Blonde, Red,... F are females. Now draw the table: ______|__M___|___F__|___Total__ B_____|__X___|_______|____30___ Not-B |_______|_______|____30___ Total _|__20___|___40__|____60___ In red, the data provided or deduced from Proposition 1 In blue the one provided by proposition 2 We're looking for X (student simultanously Males AND with Brown hair), since the probability we're looking for is X/60. Obviously, we can't find X without an additional information. X can take any value from 0 to 20. Therefore Both propositions are NOT sufficient. Answer E

I agree with E if X=Y=1, to make it simple, then 2X0 (condition 2), and that's it. Picking simple numbers is SOOOO useful sometimes !

A tells us that the product of three terms is strictly positive. It means that either all terms are positive, or an even number of terms is positive. If X > 3, all terms are positive. However, if X=1.5, for example (any number between 1 and 2 would do) then X-3 and X-2 are negative, but the product remains positive. Therefore, A is not sufficient B is obviously not sufficient A and B is still not sufficient. since values between 1 and 2 which are problematic in A are not excluded by B Answer E

Hello I would appreciate some opinions on my profile, strenghts, and weaknesses and what aspects, according to you, should be stressed in my application. Personal information - French citizen, Persian origins (half) => bicultural - 31 years old, married, one daughter 6 months old right now :D . - Languages: French native, English fluent, Spanish good, Persian academic Education - Marketing graduate degree from Top french university (Dauphine), academic grades ranging from fail in some subjects to honors or even best of the class in others. Overall, mean grade is slightly above average. - Statistics and Economics undergrad degree. Similar grades. - worked part time during all my studies in a leisure equipment store. Tests GMAT : took it three times: 640/5, 680/5.5, and last 730/97% (Q 48, 86% / V 42, 95%) AWA not available, likely to be 5.5. TOEFL : took it once. 283 Professionnal background : - Worked from jan 2002 to April 2006 in a market research institute. Was first market research analyst, then sales Consultant, then Sales and marketing manager. Expect good recommendations. Just quit this job in April , mostly because i was fed up with selling surveys and in order to concentrate on my applications. - one year Internship in a major consumer electronics manufacturer as a marketing Brand manager for europe. - several shorter internships in market research companies or in marketing positions Extracurricular - Currently coordinate First Aid and CPR courses for the French Red Cross in Paris. - Participate archeological subaquatic searchs as a scuba diver, in the river and channels of a french medieval village - At the university : President of the main student Club (one year) President of the Sailing Club (two years) Elected twice representative of the students at the University Council.(2+2) Sports : Scuba diving, Sailing (sailing instructor: organised summer courses for unfavored children, competition: won two years the regional dinghie championship), Motorbike, Skiing, ... - Numerous travels back packing (Peru, Sri Lanka, Eastern Europe, Iran, Egypt) Schools aimed: Columbia, Wharton, Berkeley, Chicago (regular MBAs), maybe NYU and Harvard Thanks in advance for answering

JISSNAR, how did you have a GPA from a French University? The grading system is completely different and grades can be hardly compared with the US system.

I agree with the method except for the end which I think can be more simple. The right triangle drawn has hypotenuse 6 and one side 3. It is a 30-60-90 triangle with sides proportional to 2-1-SQR3. You can conclude that the angle is 30 degrees thanks to that property, without using trigonometry.

MYSTERY SOLVED! I saw that question somwhere since my last post, and I confirm that it is incomplete. Actually, the information missing is the area of the parallelogram, which is given to be 18 square inches, while the sides are 6 inches long. Now, only one answer is possible, and it should be 30 degrees. By the way, the question doesn't need to state that the polygon is a parallelogram: a quadrilateral with equal sides is necessarily a parallelogram.

Well, I would say A... To know if a number N can be divided by 9, you can sum all the digits of the number, and if the number you get can itself be divided by 9, then N is a multiple of 9. It is the same property as for 3. Example 981 is a multiple of 9 since 9+8+1=18 is a multiple of 9. 681 is a multiple of 3 since 6+8+1=15 is a multiple of 3 (but not of nine) Thus if "pqr" is a multiple of nine then p+q+r is multiple of nine as well =>(1) is Sufficient

Sorry I didn't see it Thanks for ur answers anyway

Right, OA is E Thanks to all of you for your answers.

OA is A, you are right. Other method: To find whether (2) was sufficient, I finally did differently than you kk_del; if r>8%, then (1+r/100)^2 > 1.1664 We are said that (1+r/100)^2 > 1.15 so it can either be 1,1664, thus (2) is insufficient Thanks for your answers

OA is B Thanks for your answers

:smack: Eh Eh Eh, I didn't check whether the equations resulting from 1 and 2 were identical, and fell into the trap... Thanks for your posts.

Thank you for your posts. I finally found an other interesting way to solve it, quite fast. Number of Managers and Directors are m and d We all agree that 1 and 2 are, alone, insufficient. Then 1 and 2 gives the gap between a sample average (either D or M) and the hole group average. We know that the sum of the gaps with the average is always zero. So: (15000d) + (-5000m)=0 -> Obviously Sufficient and THAT'S IT!! =>d/m=1/3 so d/(m+d)=1/4 Fast, isn't it? One must just remember the property about Sum of gaps with the average at the right moment... Other methods?

Thank you to explain your method. It can be interesting to have different approaches.:hmm:

Thank you to explain your method. It can be interesting to have different approaches.:hmm:

Thank you to explain your method. It can be interesting to have different approaches.:hmm:

Thank you to explain your method. It can be interesting to have different approaches.:hmm: