adiknish

Here's my question...shouldn't the answer be "B"? I know OA is "C" but in statement (2) it says: s = -r so if s=3, then r must equal -3...right? 3=-(-3) The same is true if it is reversed; if s=-3, then r must equal 3. -3=-(3) If that is the case, why do we need statement (1), statement (2) already tells us that r and s are opposite of each other which means 0 is halfway between the two. Where is my logic off?

I got B as well, can anyone verify if OA is wrong?

#9 is E.... (1) It only tells you about two angles (and you don't know which two even) (2) It tells you about two angles, again, you don't know which two Combined: - If (2) were talking about the right angle as being twice the degree measure, then the other degree could be 45 (not 180 b/c that would disqualify it from being a quadrilateral) which would mean the last degree would be 135. -> Or it could be referring to one of the other two unknown angles which would force it to be 60 and 120 to equal the necessary 180 and still comply with the given information from (2) and complete the 360 degrees needed for the quadrilateral. ---Conclusion--- The problem is we don't know which angle (2) is referring to, so the OA of E is correct. P.S. If it makes anyone feel better this stumped me for a bit =)

How did he come up with 6x????.. DOH...never mind...i get it. It takes 6 diagonals of the square to reach the perimeter of the rectangle!!!!! EUREKA!!!!! =)

Drum X is (1/2) full of oil and drum Y, which has twice the capacity of drum X, is (2/J) full of oil. If all of the oil in drum X is poured into drum Y. then drum Y will be filled to what fraction of its capacity ? a. (3/4) b. (5/6) c. (11/12) d. (7/6) e. (11/6) Uhm...what am I supposed to do with the "J"? OA:

...and this question was on your GMAT Prep correct?

Think of it as follows. Wayne does 3 times the work (not the hours) of his son. If W represented hours, then W=3S=12 and S=4 which means that it takes Wayne 3 times as long as his son to complete a single driveway or basically Wayne takes 12 hours and his son takes 3 hours. But we know that Wayne is faster than his Son. Therefore W=ratio of Wayne work completed to S=Sons work completed. Now recall our equation for work is (W# of driveways completed/# of hours) + (S# of driveways completed/# of hours) = Total # of driveways completed/# of hours Therefore, (W=3S) which means Wayne does 12 times as much as his Son W/1 + S/1 = 1/3 or 4S=1/3 (I picked 1 for the denom, but you can pick any #. Recall its a ratio of work completed, therefore, W/S=3 and that ratio will hold no matter how many hours you pick) So, S=1/12 or 1 driveway every 12 hours

Does anyone know how to solve adding roots quickly? The question is attached Answer is I think i thought of a way..but its just taking way to long, and i don't want to have to guess.

1 is 46 2 is C Question 1 a) Time interval noising stroke = N (Noise) b) Time interval prior to next noising stroke= P (Prior) 6:00 => |1|P|2|P|3|P |4|P|5|P|6| = counting N = 6N 6:00 => |N|P|N|P|N|P|N|P|N|P|N| 6:00 => |N|1|N|2|N|3|N|4|N|5|N| = counting P = 5P The numbers illustrate the # of N's and P's that occur when the clock strikes 6:00. 22 seconds lapse during the 6:00 striking period which is equal and recall that the question states that N=P (time req'd to stroke=time b/w strokes) or 6N+5P = 22 or 6N+5N=22; 11N=22; N=2 Now at 12:00: 12:00 => |1|P|2|P|3|P| 4|P|5| P|6|P|7|P|8| P|9|P| 10|P|11|P|12| 12:00 => |N|P|N|P|N|P|N|P|N|P|N|P|N|P|N|P|N|P |N| P|N| P|N| 12:00 => |N|1|N|2|N|3|N|4|N|5|N| 6|N|7|N|8|N|9| N|10|N|11|N| OR 12N and 11 P, recall N=P and N=2, so time elapsed at 12:00 = 12N+11N 12(2)+11(2)= 46 24+22=46 Question 2 Z^n = 1 Z=? (1) N=integer and N DOES NOT = 0 Therefore, the only number raised to any number OTHER THAN ZERO is 1 or -1. (INTEGER^0 = 1, but sinces n DOES NOT = 0, Z can only be 1 or -1) Next we have to see if we deduce which Z is equal to, 1 or -1. If n = odd number and Z = -1, then Z^n = -1 If n = even number and Z = -1, then Z^n = +1 Since we do not know if n is odd or even we don't know if Z = +1 or -1 INSUFFICIENT (2)Z>0 This tells us nothing about n. 6^0 = 1 -1^0 = 1 1^1 = 1 Z can be any number. INSUFFICENT (1&2) We know from (1) that Z must equal 1 or -1 and we know from (2) that Z>0. Therefore, Z cannot be -1 and must be 1. Z=1 SUFFICENT

Agree its 1/6. But its tricky b/c it shows a -5 and not a +5 and most people just browse, see the -5 assume its +5 and count it as being able to make the equation equal 0 and then answer 1/4.

I'm with dprath....why wouldn't it be E for number two?

Nitinv....you can find it on scoretop, just do search. BUT.....Just so you know. THE QUESTIONS ARE NEARLY 100% IDENTICAL TO WHAT YOU HAVE OR WILL SEE ON THE GMATPREP!!! So if you're short on time, I wouldn't bother.

My answers (numbers correlate to jpeg file number given) 1 - A 2 - D 4 - A 5 - C 6 - D 7 - E 8 - C 11 - C 12 - E 13 - D 17 - E What are the OA's?

Correct, it would be 10.8 or 10.2.

Yes you are partially correct (and i think you get the idea, but i'm going to overdescribe just to be sure) 0.6 would be two std dev's. However, "From the mean" is the problem just telling you were to add and subtract the std deviation from. For instance, 1 std deviation from the mean is different than 1 standard deviation from the highest number.