tank

A 450 on the GMAT should be fairly easy to get. For practice, you can download 2 real tests (these are free) from www.mba.com. These are tests from sometime in the past but give you a very good idea about what to expect.

Thanks everyone. On the whole the test was pretty similar to the OG - a good mix of questions from the hard and medium difficulty bins. I was a bit nervous during the initial part of the Quant section and so goofed up on a couple of questions early in the test. However, I got a lot more relaxed after about 15 minutes and did not have a problem after that. The verbal section went pretty well. I got 4 RCs which were on interesting topics so I was able to enjoy reading them. Preparation: Quant: Kaplan GMAT, OG, TestMagic Verbal: Kaplan GMAT, Manhattan SC, OG and OG Verbal I spent the first few days doing all the questions in the Kaplan GMAT book. I was a bit rusty on Quant but it did not take too long to get back into it. Verbal was a bigger problem. After Kaplan GMAT I did the OG Verbal book. I was still having a lot of problems with SC. I then went through the Manhattan SC book 2 times and then did all the questions from the OG. Along the way I had take GmatPrep 1 and Kaplan CAT 1, 2 and 3. At this stage I realized that SC was going to be the biggest challenge for me. I then did the SC questions in the verbal OG and the OG again. However, this time I did one question at a time and then read the explanation given in the OG even if I answered the question correctly. I think this helped me the most in understanding the rules. I even read the explanations for the incorrect choices to make sure I understood why they were wrong. I cannot stress enough as to how much this helped me. I knew that if the SC questions in the real test were tough I might have a problem and so decided to concentrate on getting as many of the RC and CR questions right. I found this strategy worked well for me on the real test. Another think that I did which is different from what is suggested by most people was to spend extra time reading the RC passages. Instead of skimming through the passage and then coming back to them when I saw the questions, I would read the passage slowly. This helped me a lot. I guess this is something that you need to experiment with and see what works for you.

760 (Q49, V44) It’s finally done. Couldn’t have asked for more. Thanks to all past and present contributors for all the great questions and help during my preparation. This is indeed a great forum - Erin, thanks for setting it up.

from (1) v+z = 6 Since the only possible numbers are 1,2 and 3 we get: v = z = 3 => r = 3 (since there can be only one 3 in a column and one in a row) from(2) s+t+u+x = 6 The only way to get this is if 2 of the terms are 1 and the other 2 are 2 This makes r = 3 again Hence D

By ab I meant a+b which is the length of the diameter. As for the angles: Well, lets start with triangle which has side 'a' and assume that the smaller angle is x. Then the larger angle (which is not 90) will be 90-x Now because of the fact that ab is the dia, we know that the angle opposite ab is 90. So the smaller angle of the triangle with side b will be 90-x and the larger one will be x Hope that helps.

The answer is D. I dont understand your method (sripada) but ab should be 5. The large and small triangles (one with side "a" and the other with side "b") have the same angles and hence their sides are in proportion. Based on that we get: 2/a = b/2 Now we can substitute from (1) and (2) and either one will give the answer. a = 4 and b = 1 => ab = 5

(6C2 * 4C2 * 2C2)/3! The 3! is needed to take care of double counting.

1. C 2. B

Statement (1) a/b = c/d --- 1 does not give any information => insufficient Statement (2) sqrt(a^2) + sqrt(b^2) = sqrt(c^2) + sqrt(d^2) For purposes of distance we can take the +ve sqrt as it simply results in a reflection about one of the axis. So the above reduces to a + b = c + d ---- 2 From eqn 1 we get c = ad/b. Putting this in 2 we get: a + b = ad/b + d a + b = d(a/b + 1) Now dividing both sides by b we get: (a/b + 1) = d/b(a/b + 1) => b = d and so a = c Hence, answer is C

lsv and r1234, you are right. In my hurry I missed the fact that the number can be reduced further. 2^26/6 = 2^25/3 and based on this we should determine the remainder. Thanks for correcting me.

Congrats!! Good luck with the rest of the process.

Agree with thankout. Answers are x = -3 or x = 1/2

http://www.www.urch.com/forums/gmat-problem-solving/60994-probability.html?highlight=couple

rustyrocks, the 2 statements are true for both: x = 2 and y = 1 as well as x = 2 and y = -1 So y > 0 and y

arsingh, you are right. I did write both the statements were sufficient but accidently put C as the aswer. It should be D. Thanks