Swiss_boy

No need for GP. It is clear that s = r + 1/81 after substituing the value of r in the expression for s.

777 = n*k + 77 Since reminder is 77, 77 n*k = 700 (with values of k between 1 to 9 & n > 77) k = 1, 2, 4, 5, 7 satisfy the above equation So 5 values possible?? Whats the OA? I am sure there is a simpler way to solve

200 / 3 = 66 (number divisible by 3) 200/4 = 50 (divisible by 4) 200/12 = 16 (divisible by both 3 & 4) 66 + 50 - 16 = 100

First determine the values of X where the expression involving x changes from +ve to -ve. (inother words where the expression becomes ZERO) X = -2 and X = 2 are those points. Now consider the three scenarios. 1. X 2. X > 2 3. -2 This is what kundan did.

do you know the OA

Yeah. for AP the median is equal to mean.

It is D. x-y = 6 4x-4y = 24 => y = 24 (as 4x = 5y) - suff y + z = 36 => z = 12 (as 5y = 10 z) - suff

But question asks if the value always less than 4 or not.

Stmt 1 is NOT sufficient. for x = -1/2 and x = -7 we get different results. Statment 2 is sufficient. Answer is B.

Good one Answer is A. statement 1 ---------------- 99+99 = 198 (maximum value) 50+50 = 100 (minium value) With in this range of maximum to minimum the digit at 100 is always 1. Statment 2 ------------ maximum 3 digit number is 999 - maximum 2-digit numbers can be 31*32 minumum 3 digit number is 100 - minimum 2-digit nr can be 10*10 With in this rage 100 digit can vary from 1 to 9.

arithematic mean equal to median for "Arithmetic Progression". Stmt 1 -indicates Arithmetic progression - sufficient Stmt 2 - Ranges does not give us if the numbers are in arithmetic progression or not. So answer is A

Refer Math Forum - Ask Dr. Math If you factor a number into its prime power factors, then the total number of factors is found by adding one to all the exponents and multiplying those results together. Example: 108 = 2^2*3^3, so the total number of factors is (2+1)*(3+1) = 3*4 = 12.

IMO answer is B.

Agree with hasanth

I think correct answer is A. statment 1 - number of factors is (4+1) * (3+1) = 20 - sufficient Statment 2 cannot be sufficient. n can 5^2 * 7^3 (factors are 12) or 5^3 * 7^4 (factors are 20)