gmatfordays

Hi Ipanema, Don't let it discourage you. I myself have taken it 4 times now and have finally cracked the 600 mark. So there is hope. Use this site as much as possible. As for the PP material you can find it on the http://www.mba.com website under GMAT preparation. I assume then you do not have the official guide? Make sure to get that as well. Finally, do not let your Kaplan scores get you down. If you are scoring where you are on those tests then you can for surely score in the mid to high 600s and even into the 700s! Most importantly, assess your weeknesses, target them and lay out a study plan. You will get there. Persistance pays off!!! Trust me, I have been at it for over a year. Over the course I felt I was completely stupid, but remember the GMAT is not a test of your ability. It is a test to see if you can handle standardized testing, that is it!!! Drop me a PM if you want and I will be glad to share more. Keep your head up - it is only a test ( I know it is easy to say) but trust me you can beat it!

A box contains 3 yellow golf balls, 2 blue golf balls, and 6 white golf balls. Find the probability of selecting 5 golf balls in which at least 3 of them are white. Please explain your approach:)

I agree with vreddy and erkki. The Kaplan tests are a lot harder, but the you should use them to help build your timing. It will force you to arrive to your answer a lot quicker and or use shortcuts more often. Though don't use Kaplan as a pure reference of your scoring ability. On Kaplan I have scored anywere from 530 to 610. On PP I have scored above 700. So don't let the Kaplan scores get you down if you see yourself scoring lower than you think you should be.

Hi Zorillo, I think you can expect this type of question on the GRE or the GMAT. Though this particular question I think vreddy pulled together; I am not sure it is from a source. But yes an averages type question is surely within the realm of GRE and GMAT All the best on your test. I think your answer is correct, cause we have to take the weighted average given that we do not know how many people are in each class.

Hi Ketan, I agree with Sunxcat on this one. Do not make a quick decision based on the fact that Mississippi St offered you funding. Consider the reputation of the school as one of the highest things. Though I am not sure of your financial situation so I cannot comment on whether to go for Miss or Irvine. IMO I would go for Irvine. The UC school system in California has a strong reputation across the country. So it depends on where you want to reside afterwards as well. Though you are asking how good Mississippi state is in Comp Science/ Graphics. Should'nt you already know this, since you did apply there? Or did you just blindly pick schools and are now asking questions? Either way - weigh your options as these types of decisions (grad school) will have a big impact on your direction going forward. All the best.

It is 4C2* 13 * 4C3 * 12 ( if a !=b in a-a-b-b-b) Hi Vreddy, I was at first writing to find out if this is correct, as I was not sure if I had this question right. After writing my whole answer I now agree with your statement above, which is correct.:D

What we don't know with this question is how many people are in each class. If each class had the same amount of people then rumen's answer would be correct. But you could have a scenario where class X had 50 more people than Y and Z has 20 less than X. In this case you cannot just add the three averages and divide by 3. Looking at the other statements then x and y total should be 158 and adding the two averages 83 and 76 gives you 159 so that tells you that the class numbers are relatively close to each other. Average of Classes Y and Z should total 162, and adding them up you get 161 so again the class numbers are relatively close to each other. This then should means we can figure that the class sizes are relatively the same across each class and therefore Rumen's answer would be correct. Though knowing the type of questions that vreddy puts out - this sounds way to easy :D

Hi Thaiva, Yes I agree with you. It helps to determine where the person might sit in against the overal profile, no doubt. Cheers!

Though remember, your GMAT score is not the only thing. So trying to judge happy333's chances based on just grades and a GMAT score, will not give anyone a good guide. I know people who have low scores in both areas and have gotten into Wharton. So it is MUCH more than just your GPA and GMAT marks, IMHO.

I agree with kpadma on this one.. since its equally, that means that each must have two tasks. Though then there are permutations within that. Mayaly - C means combination.. So 10C2 means 2 selected out of a group of 10.. Check the sticky folder at the top of the problem solving section. It gives some good explanations. Hope this helps.

I figured that.. proabably a good way to destress before you take the test tomorrow:)! Damn if its not a balance scale, and I am assuming we can't use any other means. Such as water displacement, etc. Not sure.. have to think some more!:)

I am not sure what this is testing here, as this CERTAINLY will not show up on the GMAT. Hang the bag of real coins on one side of the scale and the other bag, though he does not know which is which, on the other side. If the scale is equal, then the one he did not weigh is the fake one. If the scale tips heavy , then the heavy side is the fake one.

Nice work erkki! This surely pumped me up a bit as I am going to take mine on Monday. How did the quant go this time around? Can you give us your take on it?

Thanks Ursula for your explanation. Here is a good link on rings and roundabouts. http://mathworld.wolfram.com/CircularPermutation.html

Just as an example If a fair coin is tossed twice what is the probability that it will land either heads both times or tails both times? 1. 1/8 2. 1/6 3. 1/4 4. 1/2 5. 1 Solution Let first toss be A, second B. p(Ah) = p(At) = p(Bh) = p(Bt) = 1/2 p(Ah and Bh) = p(Ah) * p(Bh) = 1/4 p(At and Bt) = p(At) * p(Bt) = 1/4 p((Ah and Bh) or (At and Bt)) = p(Ah and Bh) + p(At and Bt) = 1/4 + 1/4 = 1/2 Note that AND rule works because A and B are independent, and OR rule works because (Ah and Bh) and (At and Bt) are incompatible. Alternatively, you may use F/T rule to solve this. Enumerate outcomes as (HH, HT, TH, TT). Favorable are HH and TT. So, p = 2/4 = 1/2. Although in this case F/T rule works more gracefully, the AND/OR approach is still helpful - you can learn it on such easy examples as this to prepare for the more difficult ones.