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gmatbuster

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Everything posted by gmatbuster

  1. tvsom...thanks for the solution of h(100) +1
  2. 126 = 7*9*2 complete the squares...by multiplying by 2 and 7 => 2*7 = 14
  3. Area of triangle = (v3/4)* 6^2 = 9v3 ...i Area of circle = pi * r ^2 = pi * {(v3/2)*6/3}^2 = 3 pi ...ii area required = 1/3 (i - ii) = 3v3-pi
  4. 1. 450y =n ^3 =>3^2 * 5^2 * 2 * y = n^3 y=3*5*2^2 ans A. 2. y can be zero . x ^4 = 100, nearest is 3^4..so x had be a li'l greater than 3 but definitel less than 6. x has to lie between 3 and 6. hence answer is B
  5. Probability for Red ball = 3C1/9C1= 1/3 Probability for White ball = 2C1/9C1= 2/9 for Red followed by white = 2/27 ...i for White followed by red = 2/27 ....ii Total = i +ii = 4/24
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