rakibeeebuet

1. A 1. E

the answer will be: 3!*4!=144

ans to q 1: 2c1*4c1*7c1+2c1*4c1*3c1=80

one thing will help all that if we decrease the smallest number than the product will be decreased more but if we increase the smallest number than the product will be increased more so obviously B is greater than A.

yes it wil be: 7/12

7.If the probability of selecting 80% & higher percentage of persons for a job in a company is 0.65, then Col A: The propability of selecting persons who have less than 80% Col B: 0.35 solution: the answer is C.

If the sum of digits of a two digit number xy is 6 more than the difference between the digit at tenth place and unit digit then find the value of y? A.1 B. 2 C. 3 D. 4 E. Cannot be determined the answer will be C x+y=x-y+6 y=3

A person is supposed to collect 3 out of 5 accessories & 4 out of 5 accessories. How many such combinations can he come out of this? solution: the answer is: 5c3*5c4

1. y=-1/2 x + c x intercept = 2c y intercept = c so the answer will be A

i think computer bot is wrong. it will be: 1000x+(z-1000)y

i think the problem is not relevant for GRE. it must take few minutes to solve.

I think the language in the problem is little tricky that puzzled everyone.

i think the answers should be d and c

From the set of positive even integers between 1 and 9, 2 digits are to be chosen at random. What is the probability that the 2 digits sum to 8? solution: The set is={2,4,6,8} the only sum possible here is, 2+6=8 (only one favorable date set) but with two numbers there are 4c2=6 sum possible. (2+4 4+6 6+8 2+6 2+8 4+8) so probability=1/6

If x and y are prime numbers greater than 10 then which of the following is an even integer? A. x^2*y2 B. x^y +2 C. xy +2 D. 2xy +xy Solution: here is the answer: only A will be even as it is multiplied by 2. Except A all others are odd.